All categories

3 years ago

Log 2x=-1 solve for x

Mathematics

1 answer:

RoseWind [281]3 years ago

7 0

Answer:

= − 1 /2 :)

Step-by-step explanation:

Divide both sides of the equation by the same term

2 = − 1 2 2 = − 1 2

Simplify

Cancel terms that are in both the numerator and denominator

2 2 = − 1 2

22x=2−1 = − 1 2

x=2−1 = − 1 2

Solution

= − 1 /2 :)

You might be interested in

PLEASE HELP DO QUESTION 5 FOR BRAINLEYIST AWNSER.

zavuch27 [327]

There is no question 5?

5 0

3 years ago

Help me please I need a answer

Stels [109]

Hyy ce faci?

Spune te rog

O vai

Hai

Odată

Fățin

Temili

Plese

5 0

3 years ago

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

Answer Check

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$

The equation is true for both roots.

Answer

$\large \boxed {3 {x}^{2} - 14x - 5 = 0}$

8 0

2 years ago

What is the slope, point, x-intercept, and y-intercept?

IceJOKER [234]

X-int =(-3,0)
Y-int=(0,_1)
Slope: _1/3

5 0

3 years ago

Read 2 more answers

Which algebraic expresion is a polynomial with a degree of 2

MariettaO [177]

A polynomial with a degree of 2 can be:

x² + 1

y² + 2

etc..

hope this helps

3 0

3 years ago