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DerKrebs [107]
3 years ago
9

What multiplication problem matches this addition problem?

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0
6*7=42
It’s the answer I guess.
shepuryov [24]3 years ago
3 0
6^7=42

(6 to the 7th power equals 42)
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Lourdes has created the following challenges for you: She has given you three of the four points necessary to determine a rectan
BaLLatris [955]

Answer:

Plot each point, connect in the given order, add parallel line segments to those already there, take the coordinates of the intersection and record as answer.

a) (-1,3), (-1,2), (9,2)

  • Missing point is (9, 3)

b) (3,7), (5,7), (5,-3)

  • Missing point is (3, -3)

c) (-5,-5), (1,4), (4,2)

  • Missing point (-2, -7)

d) (-52,73), (96,73), (96,1483)

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<em>See attached</em>

5 0
3 years ago
The point (3,-1) is on the line given by which equation below?<br> HELPP MEE PLSS
faust18 [17]

Answer:

your answer will be <em><u>C. y = x-4</u></em>

Step-by-step explanation:

hope it helps you...

7 0
3 years ago
What is the measure in radians for the central angle of a circle whose radius is 8 cm and intercepted arc length is 7.2 cm? Ente
natulia [17]

The measure in radians for the central angle of the circle is; 0.9 radians.

<h3>What is the angle measure in radians of the central angle?</h3>

Since, the length of the arc is given as 7.2cm and it's radius is 8cm.

It follows that the angle measure of the central angle can be evaluated as follows;

7.2 = (A/6.28) × 2× 3.14 × 8

7.2 = 8A

A = 7.2/8

A = 0.9 radians.

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8 0
2 years ago
(13÷6)×8+6. question 2. 10×3+(7+8) please show steps Thank you
AysviL [449]
That is how u would do it

3 0
3 years ago
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Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
3 years ago
Read 2 more answers
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