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Free_Kalibri [48]
3 years ago
13

Y = -8 Y = -2x - 12 Solve this equation by substitution

Mathematics
1 answer:
aliina [53]3 years ago
5 0

Answer:

x = - 2

Step-by-step explanation:

- 8 = - 2x - 12

- 8 + 12 = - 2x - 12 + 12

- 2x = 4

- 2x ÷ - 2 = 4 ÷ - 2

x = - 2

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I think its C, not sure
Alona [7]
Yes; you are correct.
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The correct answer is:
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Answer choice:  [C]:  " x³ − 9x² + 23x <span>− 12 " .
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Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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          (x − 4) (x² <span>− 5x + 3) = 

   x * x</span>² = x³ <span>− 

   x * 5x = 5x</span>² + 

   x * 3   = 3x <span>−

   4 * x</span>²  = 4x² <span>−

   -4 * 5x =  -20x +

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</span>          (x − 4) (x² − 5x + 3) = 

x³ − 5x² + 3x −4x² − (-20x) + (-12) ;

=  x³ − 5x² + 3x −4x² + 20x − 12 ;

= x³ − 5x² − 4x² + 3x + 20x − 12 ;

= x³ − 9x²  + 23x − 12 ;  which is:
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Answer choice:  [C]:  " x³ − 9x²  + 23x − 12 " .
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7 0
3 years ago
In 1626, the Dutch bought Manhattan Island, now part of New York City, for $24 worth of merchandise. Suppose that, instead, $24
Radda [10]
2008 - 1626 -= 382

24 x (1.305)^382

= 12,229,955,10

Hope this helps
5 0
3 years ago
Read 2 more answers
What is the answer to the question
Crazy boy [7]
(42 - 14sqrt2)/5 because rationalizing means getting the root out of the denominator, which is done by multiplying the denominator by a negative or positive root depending on the situation

8 0
3 years ago
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Yuki888 [10]

(x ) = (18)
x=226
x =  \frac{226}{4 - e}
6 0
3 years ago
What is the equation of a circle whose center at (-5, -2) and radius is 2?​
aliya0001 [1]

The equation of a circle whose centre (-5,-2) and radius 2 is x^{2}+y^{2}+10x+4y+25=0

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre (h, k) radius r is

(x-h)^{2} +(y-k)^{2}=r^{2}

Given center = (-5,-2)  and Radius = 2

Put the Given value in the equation:

= (x-(-5))^{2} +(y-(-2))^{2} = 2^{2}

= (x+5)^{2} +(y+2)^{2}=2^{2}

= (x^{2} +10x+25)+(y^{2}+4y+4)= 4

= x^{2} +y^{2}+10x+ 4y+ 29 = 4

= x^{2} +y^{2}+10x +4y+ 29-4=0

= x^{2} +y^{2}+10x+4y+25=0

So, the equation of the circle whose centre is (-5,-2) and Radius 2 is

x^{2}+y^{2}+10x+4y+25=0

To read more about the equation of a circle. you can follow:

brainly.com/question/351704

#SPJ2

6 0
2 years ago
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