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2 years ago

15

Figure ZANY is a square. If ZY = 7x - 3 and ZA = 6x, what is the value of x

1 answer:

SpyIntel [72]2 years ago

6 0

7x-3=6x
x=3
..........

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What is 0.6 repeated as a fraction

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6/10 is the answer but if you want it simplified the the answer would be 3/5.

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3 years ago

What is the stander form of 1234567456

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2 years ago

Write a linear function of f with f(-3)=-2 and f(-2)=3

katrin2010 [14]

Answer:

y=5x+13

Step-by-step explanation:

when x=-3, y=-2, and when x=-2, y=3. we know that every time x increases by 1, y also increases by 5. This means that the slope is 5. to find the y-intercept, we need x to be 0. to find that, increase x by 2. if x increases by 2, then y would also increase by 10. add 10 to 3 and add 2 to -2 to get x=0 and y=13. the coordinates would be (0,13). the y-intercept is 13. now that we have enough information, we can conclude that y=5x+13. To check your answer, plug in the values for x.

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1 year ago

What is the slope of this line?<br><br> A. 1/3<br> B. 1/2<br> C. 1<br> D. 2

HACTEHA [7]

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6 0

3 years ago

Read 2 more answers

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

a

$P(\= X \ge 51 ) =0.0062$

b

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

So

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

2 years ago