Answer: (x, y) transforms into (-x, y)
Step-by-step explanation:
When we do a reflection over a given axis, the distance between the initial point to the axis must be the same as the distance of the reflected point to the axis.
So if we do a reflection over the y-axis, then the value of y must be fixed.
So if we start with the point (x, y), the only other point that is at the same distance from the y-axis is the point (-x, y)
So the rule is, the y value remains equal and the x changes of sign.
Micah is 5 inches shorter than twice the height of Jasmine
Micah = 5 inches shorter than 2 x Jasmine
Micah = 2 x Jasmine - 5 <em>(jasmine is 32 inches tall. Replace jasmine with 32)
</em>
Micah = 2 x 32 - 5
Micah = 64 - 5
Micah = 59
Micah is 59 inches tall
The four outcomes are:
HH
HT
TH
TT
There are 4 outcomes that are possible. I've never seen anyone flip and edge, so that does not count.
<h3>
ax² + bx + c = 0</h3>
<em>Let's write -9 where we see A</em><em>:</em>
<h3>
-9x² + bx + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>
<h3>
-9x² + 0.x + c = 0</h3>
<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>
<h3>
-9x² + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>
<h3>
-9x² + -2 = 0</h3>
<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>
<em>Let's put the known and the unknown on different sides:</em>
<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>
<h3>
-9x² = 2</h3>
<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<h3>
x² = 2/-9</h3>
<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>
<em>Please do not report</em><em>:</em><em>(</em>
<em>I hope I got it right, I'm trying to improve my English a little :)</em>
<h3>
<em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>
<h3>
<em><u>#XBadeX</u></em></h3>
Answer:
You didn't give the expression whose zero you want to find. From the options you wrote, the expression has two zeros, this means it is a quadratic expression.
I will however explain how to find the zero of a quadratic expression.
Step-by-step explanation:
An expression is called quadratic, if the highest degree of the variable is 2, no more, no less. It is of the form: ax² + bx + c, where a, b, and c are constants.
The zeros of a quadratic expression are the values that make the expression vanish, that is equal to zero.
Example: Find the zeros of 2x² - 6x + 4
First, equate the expression to zero
2x² - 6x + 4 = 0
Next, solve for x
2x² - 2x - 4x + 4 = 0
2x(x - 1) - 4(x - 1) = 0
(2x - 4)(x - 1) = 0
(2x - 4) = 0
Or
(x - 1) = 0
2x - 4 = 0
2x = 4
=> x = 4/2 = 2
Or
x - 1 = 0
x = 1
Therefore, the zeros of the polynomial are 1 and 2.
