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lora16 [44]
3 years ago
10

Approximate the real zeros to the nearest tenth: a.-1.6, 1.6 c.-2.6, 2.6 b.-2, 1 d .-1.6, 2.6 Please select the best answer from

the choices provided A B C D
Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Mariana [72]3 years ago
3 0

Answer:

You didn't give the expression whose zero you want to find. From the options you wrote, the expression has two zeros, this means it is a quadratic expression.

I will however explain how to find the zero of a quadratic expression.

Step-by-step explanation:

An expression is called quadratic, if the highest degree of the variable is 2, no more, no less. It is of the form: ax² + bx + c, where a, b, and c are constants.

The zeros of a quadratic expression are the values that make the expression vanish, that is equal to zero.

Example: Find the zeros of 2x² - 6x + 4

First, equate the expression to zero

2x² - 6x + 4 = 0

Next, solve for x

2x² - 2x - 4x + 4 = 0

2x(x - 1) - 4(x - 1) = 0

(2x - 4)(x - 1) = 0

(2x - 4) = 0

Or

(x - 1) = 0

2x - 4 = 0

2x = 4

=> x = 4/2 = 2

Or

x - 1 = 0

x = 1

Therefore, the zeros of the polynomial are 1 and 2.

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maks197457 [2]

6 1/2

First you find a common denominator. 1/4 = 3/12 and 1/3 = 4/12.

3/12 + 4/12 + 11/12 = 18/12.

18/12 = 6 6/12 = 6 1/2

3 0
3 years ago
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lawyer [7]
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Javion drank 7/8 quart of juice in two days. He drank 1/4 quart of juice yesterday. How much did he drink today?
o-na [289]

Step-by-step explanation:

7/8 - 1/4 = 5/8

__z_________z_

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Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

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Y= 40 explanation don’t want to just trust me it’s 40
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