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galina1969 [7]
2 years ago
6

Given that (8,-1) is on the graph of f(x), find

Mathematics
1 answer:
Nikolay [14]2 years ago
5 0

Answer:

(-12, -1)

Step-by-step explanation:

(8, -1) => (-2/3x, f(-2/3x))

therefore

-2/3x = 8

x = 8 *-3/2

x = -12

f(-2/3x) = -1

therefore, the corresponding point is:

(-12,-1)

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Answer:

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Step-by-step explanation:

5 0
2 years ago
Solve by completing the square.
enot [183]

Answer:

x^2 -8x -5 = -3

x^2 -8x -2 = 0

We complete the square by:

1) Moving the "non X" term to the right:

x^2 -8x  = 2

2) Dividing the equation by the coefficient of X²

The coefficient of x is 1 so we don't do anything

3) Now here's the "completing the square" stage in which we:

      • take the coefficient of X

that is -8

     • divide it by 2

-8 ÷ 2 = -4

     • square that number

-4*-4 = 16

     • then add it to both sides of the  equation.

x^2 -8x +16 = 2 +16

That becomes

(x -4)^2 = 18

we take the square root of both sides:

(x -4) = sqr root (18)

x1 = sqr root (18) +4

AND

(x+4) = sqr root (18) -4

x1 =  sqr root (18) +4 = 4.2426406871  + 4 = 8.2426406871

x2 = sqr root (18) -4 =  = 4.2426406871  - 4 = .2426406871

       

Step-by-step explanation:

8 0
3 years ago
A jar of natural peanut butter normally costs $4.00. Today its on sale for $3.60. What is the percent of the discount?
Alika [10]
I thought it would be 10 percent but my cal. says 1.44
4 0
3 years ago
Read 2 more answers
The right triangle above has height h centimeters and hypotenuse t centimeters. What is the area, in square centimeters, of the
White raven [17]

Answer:

A = \frac{h\sqrt{t^{2} - h^{2}}}{2}

Step-by-step explanation:

Right triangle:

height h, width w, hypotenuse h

Area is: A = \frac{h*w}{2}

Pytagoras theorem: h^{2} + w^{2} = t^{2}

In this question:

To find the area, in terms of h and t, we have to write w as a function of h and t. So

h^{2} + w^{2} = t^{2}

w^{2} = t^{2} - h^{2}

w = \sqrt{t^{2} - h^{2}}

So the area is:

A = \frac{h*w}{2}

A = \frac{h\sqrt{t^{2} - h^{2}}}{2}

8 0
3 years ago
The measure of minor arc JL is 60°.
stellarik [79]

Answer:

m∠JKL = 120°

Step-by-step explanation:

The measure of an angle formed by a two tangents drawn from a point outside the circle is the the difference of the intercepted arcs

minor arc JL = 60     major arc JL =  360 - 60 = 300

m∠JKL = 1/2(300 - 60) = 1/2(240) = 120

5 0
3 years ago
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