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3 years ago

Which expression represents the fourth term in the binomial expansion of (e + 2f)10?

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer:

Step-by-step explanation:

GuDViN [60]3 years ago

4 0

Answer:

first one

Step-by-step explanation:

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The paper usage at a small copy center is normally distributed with a mean of 5 boxes of paper per week, and a standard deviatio

VladimirAG [237]

Answer:

1.649 approximately 2

Step-by-step explanation:

S.d = standard deviation = 0.5

Time taken = lead time = 2 weeks

Mean = demand for week = 5 boxes

We are required to find the safety stock to maintain at 99% service level.

At 99% level, the Z value is equal to 2.326.

Therefore,

Safety stock = z × s.d × √Lt

= 2.326 × 0.5 x √2

= 1.649

Which is approximately 2.

7 0

3 years ago

Sally had 2/9 of a cup of pudding as a snack after school and she had 1/4 of a cup of pudding as dessert after dinner. Sally est

IrinaK [193]

Sally had about a half cup of pudding. If you make both numbers have the same denominator, you would get 8/36 and 9/36. Add them together, and you get 17/36, which is almost half.

8 0

3 years ago

tara paints 12 wall in 4 hour. she has 3 wall left to paint how long do you think that it will take her to paint the 3 remaining

Pavel [41]

12 divided by 4 equals to 3
she paints 3 wall per hour

the answer is : the remaining wall will take her 1 hour to paint

5 0

2 years ago

Read 2 more answers

Find the median of the data in the pictograph below. Caroline has 2. Samuel has 4. Abby has 4. Jason has 2

atroni [7]

Answer:

Step-by-step explanation:

The median is the central number of the data. Align numerically (2, 2, 4, 4) and find the center number. Since there are two, find the average of 2 and 4 to get 3. ([2+4]/2=3)

3 0

3 years ago

Read 2 more answers

2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago