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Elenna [48]
3 years ago
7

The circle below is centered at the point (4,1) and has a radius of length 2. What is it’s equation?

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

B

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k ) = (4, 1) and r = 2, hence

(x - 4)² + (y - 1)² = 4 → B

vekshin13 years ago
5 0

Answer:

Option B:

(x-4)^2+(y-1)^2 = 4

Step-by-step explanation:

Given

Centre = (h,k) = (4,1)

Radius = r = 2

The standard equation of circle is:

(x-h)^2+(y-k)^2=r^2

Putting the values of h,k and r

(x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4

Hence, the correct option is option B

(x-4)^2+(y-1)^2 = 4

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