Let
denote the <em>k</em>th term of the sequence. Then

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.
The sum of the first <em>n</em> terms is

From the formula for
, we get




So we have
, and
so that
.
Then the <em>n</em>th term in the sequence is

First, let's start off by simplifying as much as possible before factoring.
5d^2 - 50d + 125
We can divide all the numbers by 5 in order to simplify it:
5(d^2 - 10d + 25)
Now all we need to do is factor.
Since -5*-5 = 25 and -5 - 5 = -10, we can use this to factor:
5(d - 5)(d - 5)
Or
5(d - 5)^2
Answer:
A. Repeat the simulation several more times
Step-by-step explanation:
The purpose of the simulation model is to represent the effectivity of the passes.
The proportion of successful passes is 60%.
As we have 10 digits available, 6 (digits from 0 to 5) are used for the outcome "the pass is completed" and 4 (digits 6, 7, 8, and 9) to represent the outcome "the pass is not completed". This is correct, as it represents a probability of 60% of having a successful pass.
But to have a representative distribution of the possible and probable results, the simulation have to run enough times to have a stable distribution of the results.
Y = x - 1
y = -5 - 1
y = -6
(x, y) = (-5, -6)
y = x - 1
y = -3 - 1
y = -4
(x, y) = (-3, -4)
y = x - 1
y = 0 - 1
y = -1
(x, y) = (0, -1)
y = x - 1
y = 1 - 1
y = 0
(x, y) = (1, 0)
y = x - 1
y = 2 - 1
y = 1
(x, y) = (2, 1)
Answer:
y -3 = -1/2 x (x-1)
Step-by-step explanation: