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pogonyaev
2 years ago
7

Raul used the steps shown below to solve the equation. In which step did Raul make a mistake?

Mathematics
1 answer:
beks73 [17]2 years ago
8 0
I think it’s step 2 or 3 I’m not sur
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Kathy is paid $7.50 per hour for babysitting. If she babysits for 5 hours on Friday night, write an equation to represent how mu
nikdorinn [45]

Answer:

$37.5

Step-by-step explanation:

$7.50=in one hr

$? =in five hr

since you can cross each other

<h2>therefore the resalt it will give $37.50 right</h2>
4 0
2 years ago
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Let h(x)=2x−5 and g(x)=−3x+1.Find h(x)+g(x).? help please
Aleksandr-060686 [28]
This may look a little confusing but all you have to do is plug the equation given for h(x) which is 2x-5 in to the h(x) area in the equation where it says h(x) + g(x).

So far that’s (2x-5) + g(x)

Then,

Do the same with equation given for g(x) which is now,

(2x-5) + (3x+1)

Then solve,

2x - 5 + 3x + 1
2x + 3x- 5 + 1
5x - 4

Therefore the answer is 5x - 4.
8 0
3 years ago
Melinda wants to reduce her expenses so she can balance her budget. Which variable expense can Melinda easily adjust?
sattari [20]
B. Because you can easily just eat at home and avoid paying to eat

7 0
3 years ago
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Mika bought 9 rolls of film to take 180 pictures on a field trip. Some rolls had 36 exposures and the rest had 12 exposures. How
Juli2301 [7.4K]

The number of each type Mika bought =x = 6.8 rolls; y= 2.2 rolls.

<h3>Calculation using ratio</h3>

The number of rolls of film Mika  bought =  9 rolls

The number of rolls that had 36 exposures = x

The number of rolls that had 12 exposures = y

The total number of exposures = 36 + 12 = 48

To find the exposure by one roll = 48/9 = 5.3

If one roll = 5.3 exposure

    x roll    = 36 exposure

Make x roll the subject of formula,

x roll = 36/5.3 = 6.8 rolls

  • If one roll = 5.3 exposure

    y roll    = 12 exposure

Make y roll the subject of formula,

y = 12/5.3 = 2.2 rolls

Therefore, the number of each type Mika bought = x = 6.8 rolls; y= 2.2 rolls.

Learn more about ratios here:

brainly.com/question/2328454

#SPJ1

6 0
2 years ago
Kendra dives off a diving board into the water and then comes back up to the surface. Her dive can be modeled by the equation: ,
MAVERICK [17]

Answer:

1. 6 feet

2. 6.25 feet

3. 1 feet

4. 6 feet

Step-by-step explanation:

The equation is : $h(x)=x^2-7x+6$

1. The diving board is where Kendra dives off. Here, the horizontal distance, x from the diving board is 0.

So, substituting x = 0 in the equation, we get

$h(0)=0^2-7(0)+6$

       $=0-0+6$

       $=6$

So, the diving board is 6 feet above the surface of the water.

2. From the equation, we known that it is a parabola and the vertex is minimum.

   It is the minimum height which represents the depth Kendra dives into the water.

So the $x$ coordinate of the vertex is = $\frac{-b}{2a}$

Here, a and b are the coefficients of linear term and the quadratic terms in the equation. Therefore,

a = 1 and b = -7

∴  x coordinate = $\frac{-(-7)}{2 \times 1} $

                         $\frac{7}{2}=3.5$

Now substituting to find f(x),

$h(3.5)=(3.5)^2-7(3.5)+6$

         = -6.25

Therefore, the diver dives 6.25 feet below the water surface.

3. The horizontal distance from the board the diver enters into the water.

This is the y-intercept and it is the value of x when h(x)=0.

∴ $0=x^2-7x+6$

Factorizing, we get   $(x-1)(x-6)=0$

∴ $x=1 \text{ or}\ x=6$

So there are two solutions that are the two x intercepts of the function. Here at x = 1 shows the horizontal distance from the board from where Kendra dives into the water.

4. We know that the equation given has $\text{two}$ x intercepts. These two x intercepts  are the points where the parabola crosses the x-axis, which is the height $h(x)=0$. The height is the water surface level.

The first x intercept represents the points where Kendra dives into the water.

And the second x intercept is the point where Kendra comes out of the water surface. This this is $x=6$ for $h(x)=0$.

Thus Kendra dives out of the water surface at 6 feet from the board.

3 0
2 years ago
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