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elena55 [62]
3 years ago
5

PLEASE HELP!! What is osteoporosis? What are the symptoms and treatments?

Physics
2 answers:
eduard3 years ago
5 0
A osteoporosis is a type of bone disease that weakens your bones and may break them depending on how bad it is.

You may not have symptoms other than loss of height or bone fracture.

Some of the treatments include medication, healthy diet, weight-bearing exercise and more.
Korvikt [17]3 years ago
3 0

Explanation:

Osteopetrosis is a condition in which bones become weak and brittle. It causes the body to constantly absorb and replace bone tissue. With osteoporosis, new bone creation doesn't keep up with old bone removal.

While some don't experience symptoms, common symptoms can include bone fracture and a decrease in height.

Most treatments include supplements and diet modifications.

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A vehicle moving with a uniform a acceleration of 2m/s and has a velocity of 4m/s at a certain time .
Evgesh-ka [11]

Answer:

1 second later the vehicle's velocity will be:

v(1)= 6\,\,\frac{m}{s} \\

5 seconds later the vehicle's velocity will be:

v(5)=14\,\,\frac{m}{s}

Explanation:

Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "a"):

v(t)=v_0+a\,t

Therefore, in this case v_0=4\,\,\frac{m}{s}  and a=2\,\,\frac{m}{s^2}

so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

v(t)=v_0+a\,t\\v(t)=4+2\,\,t\\v(1)=4+2\,(1) = 6\,\,\frac{m}{s} \\v(5)=4+2\,(5)=14\,\,\frac{m}{s}

3 0
3 years ago
Tony has a mass of 50 kg, and his friend Sam has a mass of 45 kg. Assume that both friends push off on their rollerblades with t
Citrus2011 [14]

Answer:

Sam

Explanation:

Hes lighter

3 0
3 years ago
A diver can change his rotational inertia by drawing his arms andlegs close to his body in the tuck position. After he leaves th
NeX [460]

Answer:

3.14946 rad/s

Explanation:

I_i = Intial moment of inertia

I_f = Final moment of inertia

\omega_i = Initial angular velocity

\omega_f = Final angular velocity = \dfrac{2}{1.33}\times 2\pi\ rad/s

\dfrac{I_f}{I_i}=\dfrac{1}{3}

In this system the angular momentum is conserved

L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s

The angular velocity when the diver left the board is 3.14946 rad/s

3 0
3 years ago
An unknown additional charge q3 is now placed at point B, located at coordinates (0 m, 15.0 m ). Find the magnitude and sign of
Finger [1]

The first part of the question is:

Two point charges are placed on the x axis. (Attached file)The first charge, q1 = 8.00 nC , is placed a distance 16.0 m from the origin along the positive x axis; the second charge, q2 = 6.00 nC , is placed a distance 9.00 m from the origin along the negative x axis.

Answer:

q3 = +0.3nc

Explanation:

Due to the vector symbols in the solution, I've decided to attach the explanation to this answer.

5 0
3 years ago
A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti
Alenkinab [10]

Answer:

v_f = 3.45 m/s

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As we know that box was initially at rest

so here work done by all forces on the box = change in its kinetic energy

so we will have

mg sin\theta L = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 10 kg

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so we will have

10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)

2(9.81) sin10 \times 3.5 = v_f^2

so final speed is given as

v_f = 3.45 m/s

6 0
3 years ago
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