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4 years ago

Drag the tiles to the correct boxes to complete the pairs.

Physics

2 answers:

Savatey [412]4 years ago

6 0

Answer: The image below has the correct answers

zhannawk [14.2K]4 years ago

4 0

This is the match:

1) stored energy related to positions of atoms within molecules ↔ chemical energy

Explanation: the chemical energy is the energy stored in the bonds that binds the atoms that form the molecules.

2) energy released when a nucleus splits or combines ↔ nuclear energy

Explanation: there is a huge energy inside an atom which may be released when nuclei suffer fusion (combination of nuclei) or fission (split of nuclei). The fusion of atoms is what happens in stars and it is the source of their energy. Fision of atoms is the nuclear energy used in the nuclear plants to produce electricity.

3) energy related to an object's movement ↔ motion energy

Explanation:

The motion energy is the kinetic energy, KE. KE = (1/2) m* v^2

4) energy related to heigth ↔ gravitaional potential energy

The higher an object is the higher its gravitational potential energy, PE.

PE = m*g*h.

5) energy related by vibration of a string ↔ sound energy

Explanation:

Sure you have seen that: when the string of a guitar vibrate the sound is produced.

6) energy of motion of particles in a substance ↔ thermal energy

The thermal energy is the product of the motions (vibration, translation and collisions) of the molecules that form the substance. The higher the motion the the higher the thermal energy measured as temperature.

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Microwave ovens emit microwave energy with a wavelength of 12.6 cm. what is the energy of exactly one photon of this microwave r

Helga [31]

We need the frequency of the photon, it is v = c/ λ

Where c is 3 x 10^8 ms^-1 and λ is the wave length

We also need the expression of connecting frequency to energy of photon

which is E = hv where h is Planck’s constant

Combining the two equations will give us:

E = h x c/λ

Inserting the values, we will have:

E = 6.626 x 10^-34 x 3 x 10^8 / 0.126

E = 1.578 x 10^ -24 J

7 0

4 years ago

Read 2 more answers

Calculate the magnitude of the force, in newtons, exerted by a boxing glove on an opponent’s face, if the glove and face togethe

saul85 [17]

Answer:

5437.5 N

Explanation:

from the question we are given the following:

mass = 7.25 kg

initial speed (u) = 10.5 $\frac{m}{s}$

finial velocity (v) = 0

compression (s) = -7.35 cm = -0.0735 m (the negative sign is because the face is compressed, so there is a decrease)

we know that force = mass x acceleration,

we have our mass but need to find the acceleration. we can get the acceleration by applying the formula below

$v^{2} = u^{2} + 2as$

therefore

0 = 10.5^{2} + (-2)× a × 0.0735[/tex]

a = $\frac{10.5^{2} }{ 2 × 0.0735$ }[/tex]

a = 750

from F = m x a

force = 7.25 x 750 = 5437.5 N

7 0

4 years ago

Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms

lakkis [162]

Answer:

(a) 333.77 J

(b) 237.85 J

(d) 4667.85 J

Explanation:

Temperature of source, TH = 314 K

Temperature of A, Tc = 292 K

Temperature of B, Tc' = 298 K

heat taken out, Qc = 4430 J

Let the heat deposited outside is QH and QH' by A and B respectively.

$\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J$

Now

$\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J$

(a) Work done for A

W = QH - QC = 4763.77 - 4430 = 333.77 J

(b) Work done for B

W' = QH' - Qc = 4667.85 - 4430 = 237.85 J

(d) QH' = 4667.85 J

4 0

3 years ago

How to convert 7500kilometers to meters

Kazeer [188]

Answer:

7500000 metres

Explanation:

1 kilometre = 1000 metres

so 7500 kilometres would equal to 7500000 metres

7 0

3 years ago

a fluid has a density of 921 kg/m^3. at a depth of 1.22 m, the fluid pressure is 122,000 Pa. what is the pressure at the top of

Zielflug [23.3K]

Answer:

Patm or the presion at the top is equal to 110977.28[Pa]

Explanation:

First we must define the absolute pressure value, which is equal to the sum of the atmospheric pressure plus the manometrial pressure.

$P_{abs} = P_{atm}+P_{man}\\where:\\P_{abs}=122000[Pa]$

Now we can find the manometric pressure.

$P_{man} = density*g*h\\where:\\density = 921[kg/m^3]\\g = gravity = 9.81[m/s^2]\\h = depth = 1.22[m]$

$P_{man} = 921*9.81*1.22\\ P_{man}= 11022.71[Pa]$

Therefore:

$P_{atm} = P_{abs} - P_{man} \\P_{atm} = 122000 - 11022.71\\P_{atm}= 110977.28[Pa]$

4 0

3 years ago