Because this shape has 2 right angles, we can confirm that it has one set of parallel sides and is a trapezoid. Therefore, use the formula for area of a trapezoid, .5(b1+b2)(h)
.5(1+6)(12)
.5(7)(12)
42 units^2
Answer:1.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
a). There are 8 points in the figure attached.
b). There are 9 lines in the given figure.
c). There are 5 planes in the figure attached.
d). Three collinear points are D,G and F.
e). Four co-planar points are G, F, H and C.
f). Intersection of planes ABC and ABE is the common line AB.
g). Intersection of planes BCH and DEF is the common line EF.
h). Intersection of AD and DF is a point D.
Answer:
3
Step-by-step explanation:
slopes in parallel are equal
Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>