Answer:
C. Their natural predator was gone.
As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.
hence the separation distance between them is 100 cm.
now as per the question a proton is set up between them in such a way that the net force on it is zero
let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.
the force exerted by 1 coulomb on proton is-
the force exerted by 4 coulomb on proton is-![\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon%7D%20%5Cfrac%7Bq%2A4%7D%7B%5B100-x%5D%5E2%7D)
as the net force is zero,hence-

![=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B4%5Cpi%5Cepsilon%7D%20%5Cfrac%7B4%2Aq%7D%7B%5B100-x%5D%5E2%7D)
![=\frac{1}{x^2} =\frac{4}{[100-x]^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7Bx%5E2%7D%20%3D%5Cfrac%7B4%7D%7B%5B100-x%5D%5E2%7D)
![x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}](https://tex.z-dn.net/?f=x%5E2%3D%5Cfrac%7B%5B100-x%5B%5E2%7D%7B4%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5Dx%3D%5Cfrac%7B100-x%7D%7B2%7D)


cm [ans]
Answer:
True
Explanation:
This Question is a little tricky, so I am unsure if this s the most logical answer.
If you'd look at a compass, 60 degrees south is moreover south then east, and the two imaginary lines are unlikely to intercept.
Answer:
3
Explanation:
Isotopes of the same element as they have the same number of protons
Mass = 50kg
velocity = 10m/s
KE = 1/2 mv^2
= 1/2 × 50 × 10^2
= 2500J