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Fed [463]
3 years ago
14

a stone is thrown upward with a velocity of 72km/hr ,if air resistance is neglected,find the maximum height travelled by it and

the time taken for it to return to the initial positio​
Physics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

1 | \sqrt[46 \times  =  = ]{?} |

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Why did corn borers increase after the fields were sprayed for beetles?
Sergio039 [100]

Answer:

C. Their natural predator was gone.

7 0
3 years ago
A charge of +1 coulomb is place at the 0 cm mark of a meter stick. A charge of +4 coulombs is placed at the 100 cm mark of the s
UkoKoshka [18]

As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.

hence the separation distance between them is 100 cm.

now as per the question a proton is set up  between them in such a way that the net force on it is zero

let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.

the force exerted by 1 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}

the force exerted by 4 coulomb on proton is-\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}

as the net force is zero,hence-

\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}

=\frac{1}{x^2} =\frac{4}{[100-x]^2}


x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}

3x=100

x=\frac{100}{3}

=33.33333cm   [ans]







4 0
3 years ago
Read 2 more answers
I need to get into uni pls help
Dvinal [7]

Answer:

True

Explanation:

This Question is a little tricky, so I am unsure if this s the most logical answer.

If you'd look at a compass, 60 degrees south is moreover south then east, and the two imaginary lines are unlikely to intercept.

7 0
3 years ago
Atoms with the same number of protons but different numbers of neutrons are
ikadub [295]

Answer:

3

Explanation:

Isotopes of the same element as they have the same number of protons

3 0
4 years ago
An object of mass 50 kg moves with a speed of 10m/s. Calculate the kinetic energy of the object?
S_A_V [24]
Mass = 50kg
velocity = 10m/s
KE = 1/2 mv^2
= 1/2 × 50 × 10^2
= 2500J
7 0
3 years ago
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