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Two hockey players have a total momentum of +200 kg x m/s before a collision (+ is to the right). After the collision, they move
1 answer:
Total momentum after the collision: +200 kg m/s to the right
Explanation:
We can answer this question by using the law of conservation of momentum, which states that for an isolated system (=no external forces acting on the system), the total momentum is conserved.
Mathematically,
where
is the total momentum before the collision
is the total momentum after the collision
In this problem, the system consists of two hockey players. Before the collision, their total momentum is
(to the right)
Therefore, according to the law of conservation of momentum, their total momentum after the collision must be the same:
And given that the sign is +, the direction is still the same, therefore to the right.
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Answer:
532 millimeters of mercury
Explanation:
In order to convert the pressure from atm to millimeters of mercury (mm Hg), we should remind the conversion factor between the two units:
1 atm = 760 mm Hg
Therefore, we can solve the problem by setting up the following proportion:
Solving for x, we find
Answer: 13.6 N
Explanation:
The equation of motion for the rabbit is:
(1)
Where:
is the distance traveled by the rabbit
is the rabbit's initial velocity, assuming it started from rest
is the time
is the acceleration
Isolating :
(2)
(3)
(4)
On the other hand, the force is given by:
(5)
Where is the mass of the rabbit
Substituting (4) in (5):
(6)
Finally:
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
- the wheel and the axle have the same angular speed or velocity
- the speed of the plank is equal to the speed of the axle at the topmost point .
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒</em>
where
<em> - speed of the wheel</em>
<em> - angular speed of the wheel</em>
<em> - radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '' ,</em>
<em></em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '' is ,
⇒