let the numbers are x , x+1 ,x+2
∴ 6 [ x + (x+1) +(x+2) ] = 162
∴ x + (x+1) + (x+2) = 162/6 = 27
∴3x + 3 = 27
∴ 3x = 27 - 3 = 24
∴ x = 24/3 = 8
<u>So, the numbers are 8 , 9 , 10</u>
Using a theorem (yes i forgot the name of the theorem), we know that because the angles opposite of the sides are congruent, the sides must be congruent aswell. Therefore:
3x - 24 = x + 10
Now solve, starting by using the addition and subtraction properties of equality:
3x - 24 + 24 = x + 10 + 24
3x = x + 34
3x - x = x - x + 34
2x = 34
Now, use the division property of equality:
(2x)/2 = (34)/2
x = 17
Therefore, x = 17.
<em>Hope this helps! :)</em>
It should be 4x^2 (x square) +2x-1
a=4x^2, b=2x, c=-1
Use the quadratic formula to solve it which is x=-b+- square root b^2-4ac/2a
Sure the answer is obviously 9
Answer:
m∠A = 20°
Step-by-step explanation:
Triangle ABC has the following angle measures:
We know that the addition of the angles of a triangle makes 180°, therefore:
m∠A + m∠B + m∠C = 180°
Replacing with data and solving for x:
2x + 5x + 11x = 180
18x = 180
x = 180/18
x = 10°
Which makes the angles:
m∠A = 2*10 = 20°
m∠B = 5*10 = 50°
m∠C = 11*10 = 110°
