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sladkih [1.3K]
3 years ago
9

Each Grammy has a square base of 6 in wide that's 3 in more than one third of the trophies height write an equation to find a Gr

ammys height using the variable H and solve
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

The equation representing the Grammy's height is  .

The height of the Grammy is 9 inches.

Step-by-step explanation:

Given:

Base of the square = 6 inches

We need to write and solve the equation  to find a Grammy's height

Solution:

Let the Grammy's height be represented by 'h'.

Now given:

Base of the square That's 3 inches more that 1/3 of the trophy's height.

So the equation can be framed as;

Hence The equation representing the Grammy's height is .

On Solving the above equation we get;

Subtracting both side by 3 we get;

Multiplying both side by 3 we get;

Hence The height of the Grammy is 9 inches.

Good luck love!

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Bill wants to rent a car. Rental Company A charges $35 per day plus $0.10 per mile driven. Rental Company B charges $25 per day
m_a_m_a [10]
M represents miles
35+0.10m=25+0.15m
35-25+0.10m=25-25+0.15m
10+0.10m=0.15m
10+0.10m-0.10m=0.15m-0.10m
10=0.05m
m=200
Check:
35+0.10(200)=25+0.15(200)
35+20=25+30
55=55
The solution: m=200 is true.
After 200 miles driven, prices charged by both companies will be the same.
7 0
3 years ago
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Artyom0805 [142]

Answer:

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Step-by-step explanation:

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2 years ago
Find the area of the composite figure.
vodka [1.7K]

Answer:

25

Step-by-step explanation:

x = (5(3)) + (5(2))

x = 15 + 10

x = 25

4 0
1 year ago
Solve this as fast as possible please
pav-90 [236]

Answer:

X is equal to 7.

3*7+11=32

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5 0
3 years ago
Assume that​ women's heights are normally distributed with a mean given by mu equals 62.3 in​, and a standard deviation given by
Salsk061 [2.6K]

Answer: a)  0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean : \mu= 62.3\text{ in}

Standard deviation : \sigma = \text{2.4 in}

The formula for z -score :

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

a) Sample size = 1

For x= 63 in. ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29

The p-value = P(z

0.6140918\approx0.6141

Thus, the probability is approximately = 0.6141

b)  Sample size = 47

For x= 63 ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0

The p-value = P(z

=0.9772498\approx0.9772

Thus , the probability that they have a mean height less than 63 in =0.9772.

8 0
3 years ago
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