Answer:
1) 4x^(2)+11x+6 Factored--> (4x+3) (x+2)
2) 4x^(2)+10x+6 Factored--> (2x+3)(2x+2)
3) 4x^(2)+14x+6 Factored--> (x+3)(4x+2)
Step-by-step explanation:
Factor: 4x^(2)+11x+6 (<em>step by step)</em>
<em>1) Split the second term (11x) into two terms</em>
<em> </em>4x^2 + 8x + 3x + 6
<em>2)Factor out common terms in the first two terms, then in the last two terms.</em>
4x(x + 2) + 3(x + 2)
<em>3) Factor out the common term x + 2</em>
<em> </em> (x + 2) (4x + 3)
Repeat the above steps for similar questions!
Answer:
-3.25 Didn't see the whole paper so correct me if I'm wrong.
Step-by-step explanation:
−2.5+0.25+−1.25+−1.5
+1.25+0.5=-3.25
Answer:
140
Step-by-step explanation:
The arithmetic series is 5, 7, 9, 11, ........., 23.
First u have to determine the no. of terms that can be done by using
Tₙ = [a + (n - 1)d]
Tₙ-------nth term
a---------first term
n---------no.of terms in the series
d---------common difference
here a = 5,d = 2.
let it contain n terms Tₙ= [a + (n-1)d]
Substitute Tₙ, a, and d in the equation
23 = 5 + (n - 1)2
Subtract 5 from each side.
18 = (n-1)2
Divide each side by 2
(n - 1) = 9
Add 1 to each side
n = 9 + 1 = 10
The sum of the arithmetic sequence formula: Sₙ= (n/2)[2a+(n-1)d]
Substitute Sₙ, a, n and d in the equation
Sₙ= (10/2)[2(5) + (10-1)2]
Sₙ= (5)[10 + (9)2]
Sₙ= 5[10 + 18]
Sₙ= 5[28] = 140
Therefore the sum of the arithmetic sequence is 140.
