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leva [86]
3 years ago
15

Cost of a dozen pens is ₹ 180 and cost of 8 ball pens is ₹ 56. Find the ratio of the

Mathematics
1 answer:
kirza4 [7]3 years ago
5 0

Answer:

Ratio of cost of a pen to cost of a ball pen is 15:7

Step-by-step explanation:

Given that:

Cost of dozen pens = ₹180

Unit rate = \frac{180}{12}

Unit rate = ₹ 15 per pen

Cost of 8 ball pens = ₹ 56

Unit rate = \frac{56}{8}

Unit rate = ₹7 per ball pen

Ratio of cost of a pen to cost of a ball pen,

15 : 7

Hence,

Ratio of cost of a pen to cost of a ball pen is 15:7

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First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
4 0
3 years ago
The circumference of a circle is 3<br> π<br> π m. Find its diameter, in meters.
UkoKoshka [18]

Answer:

it is 8

Step-by-step explanation:

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3 years ago
Which expression is equivalent to b * b * b * b *
Ne4ueva [31]

Answer:

b⁴

Explanation:

b×b=b²     b×b=b²

b²×b=b³    b×b×b=b³

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4 0
3 years ago
Find the value of x in the figure shown below.
umka21 [38]

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7 0
2 years ago
Read 2 more answers
dos aviones parten de una ciudad con direcciones S32°E y E57°N¿ cuál es el angulo que forma sus direcciones?​
Elan Coil [88]

Answer:

El ángulo formado entre las dos direcciones es aproximadamente 115º.

Step-by-step explanation:

Las direcciones dadas en el enunciado significan lo siguiente:

S32ºE - <em>32º al este del sur.</em>

E57ºN - <em>57º al norte del este.</em>

Vectorialmente hablando, cada dirección es la siguiente:

S32ºE

A(x,y) = (\sin 32^{\circ}, -\cos 32^{\circ})

A(x,y) = (0.530, -0.848)

E57ºN

B(x,y) = (\cos 57^{\circ},\sin 57^{\circ})

B(x,y) = (0.545, 0.839)

El ángulo formado entre los dos vectores unitarios (\theta), medido en grado sexagesimales, puede determinarse mediante la siguiente ecuación vectorial:

\theta = \cos^{-1} \frac{A\,\bullet \,B}{\|A\|\cdot \|B\|}

Donde:

\|A\| - Norma de A(x,y).

\|B\| - Norma de B(x,y).

Si sabemos que A(x,y) = (0.530, -0.848), B(x,y) = (0.545, 0.839), \|A\| = 1 y \|B\| = 1, entonces el ángulo formado entre los dos vectores es:

\theta = \cos^{-1} \frac{(0.530)\cdot (0.545)+(-0.848)\cdot (0.839)}{(1)\cdot (1)}

\theta \approx 115^{\circ}

El ángulo formado entre las dos direcciones es aproximadamente 115º.

4 0
3 years ago
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