B. Warm air rises,and cool air sinks.
Answer:

Step-by-step explanation:
The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

We first compute the n-th derivative of
, note that

Now, if we compute the n-th derivative at 0 we get

and so the Maclaurin series for f(x)=ln(1+2x) is given by

Answer:
b. -13
Step-by-step explanation:
The change in temperature will be the original temperature plus or minus x, the change between a temp and b temp, to equal what the temperature is now.
Answer:
I think it's 5 or7
Step-by-step explanation:
hope it helps you
Answer:
a) x = 1.52
b) s = 1.16
Step-by-step explanation:
We have that:
5 students watched 0 movies.
9 students watched 1 movie.
5 students watched 2 movies.
5 students watched 3 movies.
1 student watched 4 movies.
(a) Find the sample mean x.
Sum divided by the number of students. So

(b) Find the approximate sample standard deviation, s.
Standard deviation of the sample.
Square root of the sum of the squares of the values subtracted from the mean, divided by the sample size subtracted by 1. So
