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2 years ago

Find y in terms with x Help me pleaseee thank uu:)

Mathematics

2 answers:

labwork [276]2 years ago

8 0

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\tt y = 90 \degree - \cfrac{5x}{2}$

____________________________________

$\large \tt Solution \: :$

The two lines are parallel, henceforth we can apply Angle pair rules.

$\qquad \tt \rightarrow \:(x + 3x + x) + 2y = 180$

[ Co - interior angles ]

$\qquad \tt \rightarrow \:5x + 2y = 180$

$\qquad \tt \rightarrow \:2y = 180 - 5x$

$\qquad \tt \rightarrow \:y = \dfrac{180 - 5x}{2}$

$\qquad \tt \rightarrow \:y = \cfrac{180 }{2} - \cfrac{5x}{2}$

$\qquad \tt \rightarrow \:y = 90 \degree - \cfrac{5x}{2}$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

cestrela7 [59]2 years ago

4 0

Answer:

y = 90 -5/2 x

Step-by-step explanation:

The angle on the left equals x+3x+x = 5x

The angle on the right equals 2y

The two angles are same side interior angles which are supplementary because the lines are parallel

5x+2y = 180

Solving for y

2y = 180-5x

Divide by 2

2y/2 = 180/2 -5x/2

y = 90 -5/2 x

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3 years ago

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3 years ago

From 19 measurements of a pressure controller, the mean operating pressure is 4.97 kPa with a standard deviation of 0.0461 kPa.

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Answer:

$4.97-2.10\frac{0.0461}{\sqrt{19}}=4.95$

$4.97+2.10\frac{0.0461}{\sqrt{19}}=4.99$

So on this case the 95% confidence interval would be given by (4.95;4.99)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =4.97$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.0461 represent the sample standard deviation

n=19 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=19-1=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.10$

Now we have everything in order to replace into formula (1):

$4.97-2.10\frac{0.0461}{\sqrt{19}}=4.95$

$4.97+2.10\frac{0.0461}{\sqrt{19}}=4.99$

So on this case the 95% confidence interval would be given by (4.95;4.99)

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Answer:

Step-by-step explanation:

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$y=kxz^2$