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creativ13 [48]
2 years ago
5

Find y in terms with x Help me pleaseee thank uu:)​

Mathematics
2 answers:
labwork [276]2 years ago
8 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

  • \tt y =  90 \degree -  \cfrac{5x}{2}

____________________________________

\large \tt Solution  \: :

The two lines are parallel, henceforth we can apply Angle pair rules.

\qquad \tt \rightarrow \:(x + 3x + x) + 2y = 180

[ Co - interior angles ]

\qquad \tt \rightarrow \:5x + 2y = 180

\qquad \tt \rightarrow \:2y = 180 - 5x

\qquad \tt \rightarrow \:y =  \dfrac{180 - 5x}{2}

\qquad \tt \rightarrow \:y =  \cfrac{180 }{2}  -  \cfrac{5x}{2}

\qquad \tt \rightarrow \:y =  90 \degree -  \cfrac{5x}{2}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

cestrela7 [59]2 years ago
4 0

Answer:

y = 90 -5/2 x

Step-by-step explanation:

The angle on the left equals x+3x+x = 5x

The angle on the right equals 2y

The two angles are same side interior angles which are supplementary because the lines are parallel

5x+2y = 180

Solving for y

2y = 180-5x

Divide by 2

2y/2 = 180/2 -5x/2

y = 90 -5/2 x

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Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
________________________________________
  A = L * w ;  we want to find the dimensions; that is, the values for
                         "Length (L)"  and "width (w)" ; 
_______________________________________
Plug in our given values:
_______________________________________
 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
                   →   (4 L²) / 4 = 9/4 ;
______________________________________
           to get:  →  L² = 9/4 ; 
 Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________          
 
     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

    →  L = 3/2 ; 

    → w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi.  =  (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
___________________________________________________
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