Answer:
6
Step-by-step explanation:
STEP
1
:
1
Simplify —
3
The equation at the end of step
1
:
12 1
—— + (((—)2) • 9) • 3)
4 3
STEP
2
:
Equation at the end of step
2
:
12 1
—— + ((—— • 9) • 3)
4 32
STEP
3
:
Canceling Out:
3.1 Canceling out 32 as it appears on both sides of the fraction line
Equation at the end of step
3
:
12
—— + (1 • 3)
4
STEP
4
:
3
Simplify —
1
Equation at the end of step
4
:
3 + 3
STEP
5
:
Pulling out like terms
5.1 Pull out 3
After pulling out, we are left with :
3 • ( 1 - (-1) ))
Final result :
6
Answer:
Step-by-step explanation:
x > 3 reads x is greater than three. This includes all numbers to the right of three, but not three itself. |₋₋|₋₋|₋₋₀---|---|---|---|---|---|----->
0 1 2 3 4 5 6 7 8 9
x ≤5 reads x is less than or equal to five. This includes all numbers to the left of and including the number 5 <--|---|---|---|---|---|---|--•₋₋₋|₋₋|₋₋₋|₋₋₋|₋₋₋₋
-2 -1 0 1 2 3 4 5 6 7 8 9
x ≥ -4 reads x is greater than or equal to minus four. This includes all numbers to the right of and including -4.
|₋₋₋|₋₋₋|₋₋₋•---|---|---|---|---|---|---|-->
-7 -6 -5 -4 -3 -2 -1 0 1 2 3
Answer:
The Answer is 1080x^21 + 2160x^20 + 3
Step-by-step explanation:
For the time period of the projectile at least 192 feet above the ground is between 2 second and 6 second
Since s=128t-16t2, we want to know the 2 times where 128t-16t2=192, as those two values will be the begin and end times of the interval in question. We can rewrite that equation in standard quadratic equation form:
16t2-128t+192=0 or, simplified, 8t2-64t+96=0
or t2-8t+12=0
since it is now in quadratic form, we can solve using the quadratic formula:
t = 2 and 6
So the time period from approximately 2 second and 6 second has the projectile above 192 feet.
Learn more about projectile here:
brainly.com/question/1659208
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Answer: y= -4x-2
Step-by-step explanation:
glad i could help!
