Answer:
Step-by-step explanation:
Independent Variable (IV): Special college preparation program
How will you describe the IV: Independent variable or known as manipulated variable is a variable where the researcher purposely manipulate the variable to see how it affect the results of the experiment.
Dependent variables (DV): Math placement scores of college applicants
How will you measure the DV: DV can be measured by recording the math placement scores of each applicants who have or have not taken the special college preparation program.
Explanation: In this case, the researcher wants to see how taking special college preparation program (IV) can affect the math placement scores of the applicants (DV). Explanation: In this case, the researcher wants to see how taking special college preparation program (IV) can affect the math placement scores of the applicants (DV).
Hypothesis:
If the applicants take the special college preparation program, the applicants will have higher math placement scores compared to the one who have do not take the program.
Answer:
30.4
Step-by-step explanation:
if you want the basic perimeter just add up all the sides
Answer:
Step-by-step explanation:
We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :
Remove the parenthesis to make it easier to read :
Multiply the numerators :
Multiply the denominators :
Apply the negative rule :
Cancel the common factor which is 18 :
Apply the addition exponent rule :
Subtract :
Apply the rule for y :
Subtract :
Cancel the common factor of z^3 :
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Thats soo many words i am sorry that i can’t help tho
