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fgiga [73]
3 years ago
11

Drag each expression to the correct category.

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

( -  \frac{4}{9} )( \frac{7}{4} )  =  \:  \: negative

( - 2 \frac{3}{4} )( - 1 \frac{1}{5} ) =  \:  \: positive

(3)( - 3)( - 3)( - 3)( - 3) =  \:  \: positive

( -  \frac{1}{6} )( - 2)( -  \frac{3}{5} )( - 9) =  \:  \: positive

( -  \frac{4}{7} )( -  \frac{3}{5} )( - 9) =  \:  \: negative

( -  \frac{10}{7} )( \frac{8}{3} ) =  \:  \: negative

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Please help me now please
riadik2000 [5.3K]

Answer:

15

Step-by-step explanation:

Area of Trapezoid: A=\frac{b_{1}+b_{2} }{2} h

Base 1 = 7

Base 2 = 3

Height = 3

Plugging into the formula, you get:

(7+3)/2 = 5

5(3) = 15

3 0
4 years ago
PLEASE HELP ASAP!!!!!Sunny earns $22.75 per week delivering newspapers. He worked as a delivery boy for 3 weeks. He also earned
alexandr1967 [171]

Answer:

error in step one

Step-by-step explanation:

Sunny earns $22.75 per week delivering. delivery boy for 3 weeks.

That means $22.75 x 3 not $22.75 + 3

He can correct his mistake by doing this:

<em>Step 1: [($22.75 * 3) + $32.75 - $14.25] * 1/ 5 </em>

<em> </em>

<em>Step 2: [$86.75] *1/5 </em>

<em> </em>

<em>Step 3: $17.35</em>

<em />

<em> </em>

<em> </em>

4 0
3 years ago
Pls help quick i need this
irina [24]

Answer:

See explanation

Step-by-step explanation:

Q1-5.

1. Plane parallel to WXT is ZYU.

2. Segments parallel to \overline {VU} are \overline {ZY}, \overline {WX} and \overline {ST}

3. Segments parallel to \overline {SW} are \overline {VZ}, \overline {YU} and \overline {XT}

4. Segments skew to \overline {}\overline {XY} are \overline {SV} and \overline {VZ} (not lie in the same plane and not parallel)

5. Segments skew to \overline {}\overline {VZ} are \overline {WX} and \overline {XT} (not lie in the same plane and not parallel)

Q6.

a. \angle 4 and \angle 10 are the same-side interior angles, transversal k

b. \angle 8 and \angle 11 are alternate exterior angles, transversal m

c. \angle 1 and \angle 4 do not form any pair of angles

d. \angle 2 and \angle 12 are the same-side exterior angles, transversal  k

e. \angle 5 and \angle 7 are corresponding angles, transversal  j

f. \angle 2 and \angle 13 are alternate interior angles, transversal l

Q7.

m\angle 1=m\angle 7=131^{\circ} (as vertical angle with angle 7)

m\angle 2=180^{\circ}-131^{\circ}=49^{\circ} (as supplementary angle with angle 1)

m\angle 8=49^{\circ} (as vertical angle with angle 2)

m\angle 3=m\angle 1=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 4=m\angle 2=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 5=m\angle 7=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 6=m\angle 8=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 10=m\angle 16=88^{\circ} (as vertical angle with angle 16)

m\angle 9=180^{\circ}-88^{\circ}=92^{\circ} (as supplementary angle with angle 16)

m\angle 15=92^{\circ} (as vertical angle with angle 9)

m\angle 14=m\angle 16=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 13=m\angle 15=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 12=m\angle 10=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 11=m\angle 9=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

Q8.

m\angle 7=m\angle 9=105^{\circ} (as vertical angles)

m\angle 8=180^{\circ}-105^{\circ}=75^{\circ} (as supplementary angle with angle 9)

m\angle 10=m\angle 8=75^{\circ} (as vertical angles)

m\angle 6=m\angle 8=75^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal c)

m\angle 1=180^{\circ}-75^{\circ}-63^{\circ}=42^{\circ} (by angle addition postulate)

m\angle 3=180^{\circ}-42^{\circ}-63^{\circ}=75^{\circ} (by angle addition postulate)

m\angle 4=m\angle 1=42^{\circ} (as vertical angles)

m\angle 5=m\angle 2=63^{\circ} (as vertical angles)

m\angle 11=m\angle 4=42^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal d)

m\angle 12=180^{\circ}-42^{\circ}=138^{\circ} (as supplementary angles)

m\angle 13=m\angle 11=42^{\circ} (as vertical angles)

m\angle 14=m\angle 12=138^{\circ} (as vertical angles)

3 0
3 years ago
Solve the inequality<br><br> (x/3) + 5 ≤ 14
faust18 [17]
\dfrac{x}{3}+5\leq14\ \ \ |subtract\ 5\ from\ both\ sides\\\\\dfrac{x}{3}\leq9\ \ \ |multiply\ both\ sides\ by\ 3\\\\x\leq27\to x\in(-\infty;\ 27]
4 0
3 years ago
Read 2 more answers
Which are the solutions of x^2 = 19x + 1?
sergey [27]

Answer:

x = \frac{19+\sqrt{365}}{2}, \frac{19-\sqrt{365}}{2}

Step-by-step explanation:

1. Move everything to one side of the equation.

x^2 - 19x - 1 = 0

2. Use the quadratic formula where a = 1, b = -19, and c = -1.

x = (-b +- sqrt(b^2-4ac)) / 2a

If you plug those numbers into that formula, you will get the result listed above

6 0
3 years ago
Read 2 more answers
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