Answer:
Red: 144. Green: 360 Brown: 552. Yellow: 144.
Step-by-step explanation:
Okay, so, to find the probabilities of red and yellow, we gotta add green and brown probabilities and then subtract that from one. Green and brown probabilities added together are 0.76. Subtract that from one and you get 0.24. Divide that by two and we get 0.12 for both red and yellow. Now we multiply 1200 by each probability.
Answer:
APart 1:
A.53 =53
B.3^5/3^-6 =177147
C.(1/4)^3 • (1/4)^2 = 1 /1024
D.(-7)^5/(-7)^7 = 1/49
Step-by-step explanation:
I tried my best for part 2 but i'm pretty sure it's not right. I think 1/1024 and 1/49 has a value between 0 and 1
Answer:
[300.202 , 329.798]
Step-by-step explanation:
The 95% confidence interval is given by the interval
![\large [\bar x-t^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x-t%5E%2A%5Cfrac%7Bs%7D%7B%5Csqrt%20n%7D%2C%20%5Cbar%20x%2Bt%5E%2A%5Cfrac%7Bs%7D%7B%5Csqrt%20n%7D%5D)
where
<em>is the sample mean </em>
<em>s is the sample standard deviation </em>
<em>n is the sample size (n = 7) </em>
is the 0.05 (5%) upper critical value for the Student's t-distribution with 6 degrees of freedom (sample size -1), which is <em>an approximation to the Normal distribution for small samples (n<30).</em>
Either by using a table or the computer, we find
and our 95% confidence interval is
![\large [315-2.447*\frac{16}{\sqrt{7}}, 315+2.447*\frac{16}{\sqrt{7}}]=\boxed{[300.202,329.798]}](https://tex.z-dn.net/?f=%5Clarge%20%5B315-2.447%2A%5Cfrac%7B16%7D%7B%5Csqrt%7B7%7D%7D%2C%20315%2B2.447%2A%5Cfrac%7B16%7D%7B%5Csqrt%7B7%7D%7D%5D%3D%5Cboxed%7B%5B300.202%2C329.798%5D%7D)
Answer:
Step-by-step explanation:
=> 
[
]
=> 3.64 + 0.6
=> 4.24
Hope this helped!
~AnonymousHelper1807
The answer is C.
<span>C. A markup has no limit, but a markdown is limited to 100% or less. </span>
