3 years ago

Trigonometry answer need

Mathematics

1 answer:

Sladkaya [172]3 years ago

3 0

That is the answer..............

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tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

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$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

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