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Marina86 [1]
3 years ago
8

Trigonometry answer need

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
That is the answer..............
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Solve the system of equations.
dolphi86 [110]

Answer:

the answer is b

b works for each equation

Step-by-step explanation:

4 0
3 years ago
If the Jackson family drive 135 miles on 6 gallons of gas, how many miles can they can they drive on 9 gallons?
drek231 [11]

Answer:

202.5 miles

Step-by-step explanation:

We find the unit rate of the mile per gallon

135/6

= 22.5

We multiply 22.5 by 9 to get the miles they can drive on 9 gallons

22.5 * 9

= 202.5

3 0
2 years ago
Read 2 more answers
Calculate the volume of a cylinder, radius 12.5 cm and height 14 cm
Morgarella [4.7K]
\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=12.5\\
h=14
\end{cases}\implies V=\pi \cdot 12.5^2\cdot 14
6 0
3 years ago
What is the distance from C to D?<br><br> A. 5 units<br> B. 1 unit<br> C. 25 units<br> D. 7 units
Vera_Pavlovna [14]

Answer:

Option A

Step-by-step explanation:

According to the distance formula , for any 2 points P & Q whose coordinates are (x¹ , y¹) and (x² , y²) respectively. So ,

PQ = \sqrt{(x^{2} - x^{1} )^{2} + (y^{2} - y^{1})^{2} }

NOTE = HERE x² , y² DOESN'T MEAN THE SQUARES OF x & y . THEY ARE JUST COORDINATES.

According to the question ,

Coordinate of C = (2 , -1)

Coordinate of D = (5 , 3)

Using distance formula ,

CD = \sqrt{(5-2)^{2} + (3 -(-1))^{2} }

=> CD = \sqrt{3^{2} + 4^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5

5 0
3 years ago
10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!
Lilit [14]
After a little manipulation, the given diff'l equation will look like this:

e^y * dy = (2x + 1) * dx.
                                                             x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
                                                               2

Now let x=0 and y = 1, o find c:

e^1 = 0^2 + 0 + c.  So, c = e, and the solution is e^y = x^2 + x + e.
4 0
3 years ago
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