Answer:
Step-by-step explanation:
G=30t+40, C=20t+60, C=G
30t+40=20t+60, subtract 40 from each side
30t=20t+20, subtract 20t from each side
10t=20, divide each side by 10
t=2
So both garages charge the same fot two hours of work.
I believe -3(2n)2 is equal to -6n(2)
It is 3 units down to parent function
F = 1.8C + 32
С = -10 ⇒ F = 1.8·(-10) + 32 = 14 ⇒
(-10, 14)С = 0 ⇒ F = 1.8·(0) + 32 = 32 ⇒
(0, 32)
С = 10 ⇒ F = 1.8·(10) + 32 = 50 ⇒
(10, 50)С = 20 ⇒ F = 1.8·(20) + 32 = 68 ⇒
(20, 68)