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Virty [35]
3 years ago
12

PLSSS HELPPP MARKING BRAINLIST !!!!!!

Mathematics
1 answer:
ioda3 years ago
4 0

Answer:

<em>First Option; 40,</em>

<em>Second Option; x = 3,</em>

<em>Third Option; x = - 5,</em>

<em>Fourth Option; x = 0</em>

Step-by-step explanation:

Given the expression x^2 + 3 * ( x + 4 ), where x = 4;

x^2 + 3 * ( x + 4 ) ⇒ Substitute the value of 4 in replacement of x,

( 4 )^2 + 3 * ( 4 + 4 ) ⇒ Add the terms in ( ), taking 4^2 at the same time,

16 + 3 * ( 8 ) ⇒ By PEMDAS, multiply 3 by 8 first,

16 + 24 ⇒ And now add the remaining terms,

<em>Solution; 40</em>

This next equation is given to be 5 * ( 2x - 1 ) = 25, where we must solve for x;

5 * ( 2x - 1 ) = 25 ⇒ Distribute the 5 to the terms in ( ),

10x - 5 = 25 ⇒ Add 5 on either side of the equation,

10x = 30 ⇒ Divide 10 on either side of equation,

<em>Solution; x = 3</em>

Here we must solve for the value of x provided the equation 6x + 4 - x = 2x - 11;

6x + 4 - x = 2x - 11 ⇒ Add 11 on either side,

6x + 15 - x = 2x ⇒ Add x on either side of equation,

6x + 15 = 3x ⇒ Subtract 6x on either side,

15 = - 3x ⇒ Divide 3 on either side,

<em>Solution; x = - 5 </em>

Now we are given the equation 4 - ( 3x + 4 ) = - 9x, solving for the value of x;

4 - ( 3x + 4 ) = - 9x ⇒ Distribute the - 1 to all terms in ( ),

4 - 3x - 4 = - 9x ⇒ Add 3x on either side of equation,

4 - 4 = - 6x ⇒ Subtract 4 from 4,

0 = - 6x ⇒ Divide - 6 on either side,

<em>Solution; x = 0</em>

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PLEASEEE HELP ! I WOULD APPRECIATE IT VERY MUCH :)
azamat

hi!

so the original equation is (x^2 -121) / x+ 11.

Those two equations look similar...

well, we know that the top equation looks like a^2 - b^2, and that equation iis equivalent to this equation: (a+b)(a-b).

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we can cancel the x+11 on the top and the x+11 on the bottom out.

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