Question 4 (Essay Worth 10 points) (06.04 HC) A figure is located at (2.0), (2, -2), (6, -2), and (6.0) on a coordinate plane. W
1 answer:
You might be interested in
Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is
8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055
Answer:
c= 17
Step-by-step explanation:
c² = a² + b²
c= ?
a = 8
b= 15
c² = (8)² + (15)²
c² = 64 + 225
c² = 289