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2 years ago

5

Segments AB and CD coincide.

2 answers:

Westkost [7]2 years ago

7 0

Answer: it’s the first one

Step-by-step explanation:

laila [671]2 years ago

4 0

Answer:

A

Step-by-step explanation:

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What is 2 times 2 times 2 times 2?

kolezko [41]

The answer 16 (sixteen)

7 0

3 years ago

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In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?

WITCHER [35]

4sqrt(3)

See the diagram below.

5 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

When Marco swim, the number of calories burned after time x, In minutes, is given by the equation

Cloud [144]

Answer : 4. 576

Y= 330 + 8.2(30)

330 +246

576

4 0

3 years ago

The cost to print digital photos at a local store is

snow_tiger [21]

<h2>The cost is same for both the options if we purchase 27 photos</h2>

Step-by-step explanation:

Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as $C_{1}(x)=0.25x$ .

Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as $C_{2}(x)=2.70+0.15x$ .

Let us assume both costs are the same if we purchase $n$ photos.

So, $C_{1}(n)=C_{2}(n)$

$0.25n=2.70+0.15n$

$0.10n=2.70$

$n=27$

∴ On purchasing 27 photos, cost for both the options is the same.

5 0

3 years ago

Read 2 more answers