We are given that 14 inch represent 38 foot.
To know the model length that represents 1 foot, all we have to do is cross multiplication as follows:
14 inch ..............> 38 foot
?? inch .............> 1 foot
length on model = (1*14) / 38
length on model = 7/19 inch = 0.36842 inch
Answer:
Step-by-step explanation:
9). -2.2(4 - 1.9x) = 3.3(0.2x - 0.8)
-8.8 + 2.2(1.9x) = 0.66x - 2.64
-8.8 + 4.18x = 0.66x - 2.64
4.18x - 0.66x = 8.8 - 2.64
3.52x = 6.16
x = 1.75
10). 3.2(1 + 2.6x) = 2.4(x - 3.6)
3.2 + 8.32x = 2.4x - 8.64
8.32x - 2.4x = -3.2 - 8.64
5.92x = -11.84
x = 2
11). 4.6(2x - 5.5) = 3.9 + 0.8(1 + 5.5x)
9.2x - 25.3 = 3.9 + 0.8 + 4.4x
9.2x - 25.3 = 4.7 + 4.4x
9.2x - 4.4x = 25.3 + 4.7
4.8x = 30
x = 6.25
12). 0.2(3x + 2.5) - 4.9 = 3.8 - 2.2(x - 5.5)
0.6x + 0.5 - 4.9 = 3.8 - 2.2x + 12.10
0.6x - 4.4 = -2.2x + 15.90
0.6x + 2.2x = 15.90 + 4.4
2.8x = 20.30
x = 7.25
Select the correct answer. which data set is the farthest from a normal distribution? a. 2, 3, 3, 4, 4, 4, 5, 5, 6 b. 3, 4, 5, 6
tigry1 [53]
The answer choice which is the farthest from a normal distribution is; Choice E; 2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10.
<h3>Which data set is farthest from a normal distribution?</h3>
A normal distribution, is a data set which when graphed must follow a bell-shaped symmetrical curve centered around the mean. Additionally, such distribution must adhere to the empirical rule that indicates the percentage of the data set that falls within (plus or minus) 1, 2 and 3 standard deviations of the mean.
On this note, upon evaluation of the data sets, it follows that answer choice E represents the data set that's most farthest from a normal distribution.
Read more on normal distribution;
brainly.com/question/26678388
#SPJ4
Answer:
∠O = 95°
Step-by-step explanation:
since ∠Q = 85°, arc NOP = 2(85°) = 170°
arc PQN = 360° - arc NOP
arc PQN = 360° - 170° = 190°
∠O = 1/2(arc PQN) = 1/2(190°) = 95°
Answer:
12
Step-by-step explanation:
A rhombus is a parallelogram with all four sides equal.
Its diagonals are perpendicular.
Each of the triangles formed by the diagonals and the sides are congruent, so the area of the rhombus is 4 times the area of one of the triangles.
Since the short diagonal is given as 4, each of the triangles can be viewed as having a base of 2. Each triangle's height, h, then is one half the length of the long diagonal.
The are of one of the triangles is 1/2 (base)(height)=(1/2)(2)h
The area of the rhombus is then
4(1/2)(2)h=24
Solving for h gives
h=6
This makes the length of the long diagonal 2h=12
