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neonofarm [45]
3 years ago
8

Circle A was translated 3 units to the left and 4 units up to create Circle B. Which rule describes the translation that was app

lied to Circle A to create Circle B?
Mathematics
1 answer:
kifflom [539]3 years ago
4 0

Answer:

B = (x - 3, y + 4)

Step-by-step explanation:

Given

Represent the coordinates of circle A with (x,y)

<u>Translation</u>

Left = 3 units

Up = 4 units

Required

Determine the coordinates of B

When a point (x,y) is translated by h units left, the new point is: (x - h, y)

When a point (x,y) is translated by b units up, the new point is: (x, y + b)

So, when circle A is completely translated to B, the new points of B is:

B = (x - h, y + b)

In this case:

h = 3\ and\ b = 4

So:

B = (x - 3, y + 4)

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\displaystyle \rm  A_{ \text{c  - pentagon}} =41

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Step-by-step explanation:

we have a square and a triangle

we want to figure out the area and the perimeter of the pentagon

to figure out the area of the pentagon we can use the given formula:

\displaystyle \rm  A_{ \text{c  - pentagon}} = A_{ \text{squre}} - A_{ \text{triangle}}

let's figure out A_{\rm square}:

since the given shape is a square Every angle of its 90° Thus the triangle is a right angle triangle

therefore the height is 4

\displaystyle A _{ \rm triangle} =  \frac{1}{2}  \times b \times h

substitute h and b

\displaystyle A _{ \rm triangle} =  \frac{1}{2}  \times 4 \times 4

reduce fraction:

\displaystyle A _{ \rm triangle} =   2 \times 4

simplify multiplication:

\displaystyle A _{ \rm triangle} =   8

likewise square

\displaystyle A _{ \rm squre} =  {s}^{2}

substitute s:

\displaystyle A _{ \rm squre} =  {7}^{2}

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\displaystyle A _{ \rm squre} =  49

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\displaystyle \rm  A_{ \text{c - pentagon}} =49- 8

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to figure out perimeter

let's figure out hypotenuse first

\displaystyle h =  \sqrt{ {4}^{2}   +  {4}^{2} }

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\rm \displaystyle P _{ \rm c - pentagon} = 6 + 4 \sqrt{2}  + 14

\rm \displaystyle P _{ \rm c - pentagon} =  20+ 4 \sqrt{2}

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