Question

Hey i really need help with this. thank you:))

Answer 1

Given:

$L=2\dfrac{1}{2}$ ft and $W=3\dfrac{2}{5}$ ft.

$P=2L+2W$

To find:

The value of P.

Solution:

We have,

$P=2L+2W$

Substituting $L=2\dfrac{1}{2}$ and $W=3\dfrac{2}{5}$, we get

$P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}$

$P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}$

$P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}$

$P=5+\dfrac{34}{5}$

Taking LCM, we get

$P=\dfrac{5(5)+34}{5}$

$P=\dfrac{25+34}{5}$

$P=\dfrac{59}{5}$

$P=11\dfrac{4}{5}$

Therefore, the value of P is $11\dfrac{4}{5}$ ft.