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Shkiper50 [21]
3 years ago
15

Solve the equations below for x. Please show your math work step by step.

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

x = 14 and x = - 7

Step-by-step explanation:

Not that + (- ) = -

(a)

x + (- 4) = 10, that is

x - 4 = 10 ( add 4 to both sides )

x = 14

(b)

2x - 10 = - 24 ( add 10 to both sides )

2x = - 14 ( divide both sides by 2 )

x = - 7

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Learn with an example
malfutka [58]

Answer:

200

Step-by-step explanation:

1. 4 times 5 because there are 5 types in total and they make 4 of each type in each batch they bake. 4*5 is 20.

2. 20 times 10 because they make 10 batches and you know there are 20 in each batch. so 20 times 10 is 200.

200 is the answer.

4 0
3 years ago
The following a function (6,3), (-1,2), (-1,-1), (4,3)
Akimi4 [234]

for an expression or relation to be a function, it must not have any x-coordinate values repeated, let's check this one

\bf (6,3), (\stackrel{\stackrel{rep eated}{\downarrow }}{-1},2), (\stackrel{\stackrel{rep eated}{\downarrow }}{-1},-1), (4,3)\qquad \textit{not a function}

5 0
2 years ago
If 2^5 x 5^2 = 2^n x 10^2, what is the value of n?
Marat540 [252]

Answer: x = 0

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

7 0
3 years ago
According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not
Lorico [155]

Answer and Step-by-step explanation:

From the question statement we get know that it is Binomial distribution because there are only two possible outcomes so we need to use Binomial Probability Distribution for this question.

Formula for the Binomial Probability Distribution:

P(X)=   p^x q^(n-x)

Where,

  • C_x^n=n!/(n-x)!x!   (i.e. combination)
  • x= total number of successes
  • p=probability of success (p=1-q)  
  • q=probability of failure (q=1-p)
  • n=number of trials
  • P(X)= probability of total number of successes

Answer and explanation for each part of the question are as follow:

a.What is the probability that among 10 randomly observed individuals exactly 4 do not cover their mouth when sneezing?

Solution:

Given that

n=10  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=4 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-4)!4!=210

P(X)=C_x^n   p^x q^(n-x)=210×〖(0.267)〗^4×〖0.733〗^(10-4)

P(X)=210×0.00508×0.155  

P(X)=0.165465  

b. What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth when sneezing?

Solution:

Given that

n=10  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=3 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-3)!3!=120

P(X)=C_x^n   p^x q^(n-x)=120×(0.267)^3×〖0.733〗^(10-3)

P(X)=120×0.01903×0.1136  

P(X)=0.25962  

c. Would you be surprised if, after observing 18 individuals, fewer than half covered their mouth when sneezing? why?

Solution:

Given that

n=18  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=9 (x is the number of successes “number of individuals not covering their mouths when sneezing”, if less than half cover their mouth then more than half will not cover), so let x=9

C_x^n=n!/(n-x)!x!=18!/(18-9)!9!=48620

P(X)=48620×(0.267)^9×〖0.733〗^(18-9)  

P(X)=48620×0.00000689×0.0610  

P(X)=0.020  

Yes, I am surprised that probability of less than 9 individuals covering their mouth when sneezing is 0.020. Which is extremely is small.

3 0
3 years ago
Craig scored 12 points in a game. Marla scored twice as many points as Craig but 5 fewer than Nelson scored. Write an expression
asambeis [7]
First write what are given from the question
We write "<span>Craig scored 12 points in a game" as
</span>⇒ c = 12 <em>(first equation)</em>
We write "<span>Marla scored twice as many points as Craig but 5 fewer than Nelson scored" as
</span>⇒ m = 2c <em>(second equation)</em>
⇒ m = n - 5 <em>(third equation)</em>
<span>
Second, find the expression for n based on what we write above
</span>From the second and third equation
⇒ m = m
⇒ n - 5 = 2c
Subtitute from the first equation
⇒ n - 5 = 2c
⇒ n - 5 = 2(12)
⇒ n - 5 = 24

This is the expression to find how many nelson scored
n - 5 = 24
<span>
</span>
4 0
2 years ago
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