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Shkiper50 [21]
3 years ago
15

Solve the equations below for x. Please show your math work step by step.

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

x = 14 and x = - 7

Step-by-step explanation:

Not that + (- ) = -

(a)

x + (- 4) = 10, that is

x - 4 = 10 ( add 4 to both sides )

x = 14

(b)

2x - 10 = - 24 ( add 10 to both sides )

2x = - 14 ( divide both sides by 2 )

x = - 7

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Solve for x: <br> dx+fx=8-2dx
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fx=8-3dx

Step-by-step explanation:

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Please help me ASAP. ​
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<h3><u>Solution: </u></h3>

Radius of Cylindrical Pillar , r = 28 Cm = 0.28 m.

  • Height, h= 4 m.

Curved surface area of a Cylindrical = 2πrh.

Curved surface area of a pillar -

=  >  \: 2 \times   \frac{22}{7}  \times 0.28 \times 4 = 7.04 {m}^{2}

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Akimi4 [234]
-6×-6=36
f-34=36
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7 0
3 years ago
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jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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