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Rufina [12.5K]
3 years ago
11

Write the radical in simplest radical form √5/8

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

\dfrac{\sqrt{10}}{4}

Step-by-step explanation:

\sqrt{\dfrac{5}{8}} =

= \dfrac{\sqrt{5}}{\sqrt{8}}

= \dfrac{\sqrt{5}}{\sqrt{4 \times 2}}

= \dfrac{\sqrt{5}}{2 \sqrt{2}}

= \dfrac{\sqrt{5}\sqrt{2}}{2 \sqrt{2}\sqrt{2}}

= \dfrac{\sqrt{10}}{2 \times 2}

= \dfrac{\sqrt{10}}{4}

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Answer:

t= 24.75 days

Step-by-step explanation:

Here A(t) is the amount of the element that remains after some time. So they tell us that find the time it takes to basically have 4 grams remaining so A(t) = 4

4 = 10 * 0.5 ^ (t/18.72)

0.4= 0.5 ^ (t/18.72)

t= 24.75 days

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A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

Step-by-step explanation:

Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

Hence, The required fraction = \dfrac18

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