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rosijanka [135]
3 years ago
10

PLEASE HELP! THIS IS DUE TONIGHT! THANK YOU!! EXPLANATION = BRAINLIEST

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

Step-by-step explanation:

18/6=51/p

do cross multiplication

6*51=p*18

306/18=p

17=p

therefore perimeter is 17 cm

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Use the graph to write a linear function that relates y to x
Alla [95]
81- answer is ok but im not suree
3 0
2 years ago
A number is increased by 2 and then multiplied by 3. The result is 24. What is this number
Sav [38]

Answer:

The answer is 6.

Step-by-step explanation:

To find this answer, divide 24 by 3 and you get 8. 8 minus 2 is 6.

3 0
3 years ago
What is the midpoint of QR. Q(2,4) and R(-3,9)
Eduardwww [97]

Answer:

The answer is

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q(2,4) and R(-3,9)

The midpoint is

M = ( \frac{2 - 3}{2}  \:  , \:  \frac{9 + 4}{2} ) \\

We have the final answer as

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Hope this helps you

6 0
3 years ago
What is the solution set of {x | x < 2} {x | x ≥ 2}? all numbers less than -5 and greater than 5 the empty set the numbers be
juin [17]

Answer:

The solution set is the empty set.

Step-by-step explanation:

{x | x < 2} is the set of all numbers less than 2. This means x can take values such as 1.99, 0, -2000 and so on. That is, all values less than 2.

{x | x ≥ 2} is the set of all numbers equal to or greater than 2. This means x can take values such as 2, 2.1, 5000, and so on. That is, 2 or any value greater than 2.

Since there is no sign between the two sets, the question is asking for the intersection between these two sets. That is, what elements are common to these two sets? As we can see, the two sets don't have any common element. Hence, their intersection is the empty set.

(Note that the union of these two sets would be the set of all real numbers as that includes all elements from either set).

3 0
3 years ago
Please help ASAP !!! Thank you !
snow_tiger [21]
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>

<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>

<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>

<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>

8 0
3 years ago
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