The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)
Solution:
As per the problem
A person is born every 5 seconds and a person dies every 12 seconds.
Here the LCD of 5 and 12 is 60.
The number of person born in 60 seconds
The Number of person died in 12 seconds
Hence Population increase in 60 seconds is
Hence time required to increase the population by one 
Answer: Right angled triangles and parallelograms; Pythagorean triplets, triangles meet maths; Shadows and right triangles (radius of the Earth). The right ...
Step-by-step explanation:
Answer:
x>3
Step-by-step explanation:
