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Alchen [17]
3 years ago
5

Someone do this and explain for brain liest :D explain how u do it and yes

Mathematics
1 answer:
Sonja [21]3 years ago
6 0

Answer:

16/ 2/3

Step-by-step explanation:

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Which function is represented by the input-output table below? ( please help and thank you)
horsena [70]

the answer is A

 if you multiply x by 3 then add 2 you get f(x)

8 0
4 years ago
Which equation models a line that is perpendicular to y = x - 1 and goes through the point (5,4)
PtichkaEL [24]

Answer:

y = - x + 9

Step-by-step explanation:

Because the line is perpendicular, the slope with be the opposite reciprocal. So, if the slope is 1 as in the equation y = x - 1, the opposite reciprocal is -1.

So the equation that is perpendicular will look like this so far:

y = -x + b   (b represents our y-intercept that we have not found yet)

Now we will find the y-intercept. We can find it by substituting the coordinates (5,4) as x and y into the equation right above ^^.

So,  4 = -(5) +b     or     4 = -5 + b

Add 5 to both sides to isolate b on the right side. b = 9

Therefore, the y-intercept is 9.

Now we have found everything we need for the equation, which is

y = - x + 9

8 0
4 years ago
PLEASE HELP
wlad13 [49]

Answer:

The mistake is in step 1 when you do -2(x+4) you do the distributive property first -2 times x is -2x that's correct but -2 times 4 is not 8 it is -8

when you multiply by negatives the answer will always be a negative unless your multiply 2 negative number together then itll be positive ex. 4 × -4 = -16 (negative) but -4 × -4 = 16 (positive)

4 0
3 years ago
Write an equation of the line that is:
zlopas [31]
Lines that are parallel will have the same slope. Lines that are perpendicular will have slopes that are the negative reciprocal of each other.

<em>(a) </em><span><em>parallel to the line y=2x-4, and has a y-intercept of 7</em>
</span>slope of first line: 2
slope of second line: 2
y=mx + b
<span>y=2x+7
</span>
<em>(b) parallel to the line y-3x=6, and has a y-intercept of -2</em>
y=3x+6
slope of first line: 3
slope of second line: 3
y=mx + b
y=3x-2

<em>(c) </em><span><em>parallel to the line 2x+3y=12, and that passes through the origin</em>
</span>3y=-2x+12
y=-2/3x+4
slope of first line: -2/3
slope of second line: -2/3
origin: (0,0)
y=mx + b
y=-2/3x + 0
y=-2/3x

<em>(d) </em><span><em>perpendicular to the line y=3x+2, and has a y-intercept of 2</em>
</span>slope of first line: 3
slope of second line: -1/3
y=mx + b
y=-1/3x + 2

<em>(e) </em><span><em>perpendicular to the line 3y+4x=18, and that passes through the origin</em>
3y=4x+18
y=4/3x+6
</span>slope of first line: 4/3
slope of second line: -3/4
origin: (0,0)
y=mx + b
y=-3/4x + 0
y=-3/4x
3 0
3 years ago
In a ΔPQR, ∠Q = 90 , PQ = 5 cm, QR = 12cm. If QS is the altitude then QS is equal to?
ryzh [129]

Answer:

QS EQUAL TO IS ?

Step-by-step explanation:

In a ΔPQR, ∠Q = 90 , PQ = 5 cm, QR = 12cm. If QS is the altitude then QS is equal to?

4 0
3 years ago
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