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zhenek [66]
3 years ago
5

What is (3x+12)-(6x+5)

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer: -3x + 7

Step-by-step explanation: All you have to do is combine like terms

First, you combine 3x - 6x which, will give you -3x

Second, you combine 12 - 5 which will give you 7

  3x - 6x = -3x

  12 - 5 = 7

So, combine the answers and you will get -3x + 7

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A rectangle has a perimeter of 52 cm and an area of 144 square cm. Find its length and width if they are in whole numbers.
Bingel [31]
8 and 18:
8+8+18+18= 52
8*18 = 144

Tada!
6 0
3 years ago
Need help solving this problem ​
natka813 [3]

Answer:

Part 1: \frac{11-x}{5} or \frac{11}{5}-\frac{x}{5}

Part 2: \frac{9}{5}

Step-by-step explanation:

To start things off, you must put everything on the opposite side of y so that you only have the y variable left.

In this case, put x onto the other side, making it negative since it's flipped, so you get 5y=11-x (since the x is negative you're using subtraction from 11).

Next, divide both sides by 5 to make 5y into y:

\frac{5y}{5} =\frac{11}{5}-\frac{x}{5}

y=\frac{11}{5}-\frac{x}{5}

Then in this case you turn y=f(x), but the system did it for you, so all you have to put is \frac{11}{5}-\frac{x}{5}.

For the second part you must replace x with 2 since you need to find f(2).

\frac{11-2}{5}

Your answer for part 2 is \frac{9}{5}.

3 0
2 years ago
I need help with this please pls pls
Masja [62]

Answer:in what ?

Step-by-step explanation:

7 0
3 years ago
$14.65 plus what equals $65.00?
ziro4ka [17]

79.65

I used a calculator

5 0
2 years ago
Read 2 more answers
Can any negative integer be greater than a positive integer explain
Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

y < 0 < x

and since the relation of order "<" is transitive, this implies

y < x

5 0
3 years ago
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