Answer:
A. 1 rectangle, 2 triangles
B. AB = AE = 5
C. 36.5 square units
Step-by-step explanation:
<h3>A.</h3>
The attached figure shows 1 rectangle (square) and two triangles.
__
<h3>B.</h3>
These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:
AB = 2 -(-3) = 5
AE = 3 -(-2) = 5
__
<h3>C.</h3>
The area of the square is ...
A = s^2 = 5^2 = 25
The area of triangle BCF is ...
A = 1/2bh = 1/2(3)(5) = 15/2
The area of triangle CDE is ...
A = 1/2bh = 1/2(8)(1) = 4
The total area is the sum of the areas of the square and two triangles:
total area = 25 +7.5 +4 = 36.5 . . . square units
_____
<em>Additional comment</em>
We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...
A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5
Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...
32.5 +4 = 36. 5 . . . . square units
Answer:
b=(13/4, -27/4, -4)
Step-by-step explanation:
A.x=b
x=(a, b, c)
a - b + 2c = 2
3a + b + 0 = 3
0 + 0 + c = -4
solving this system
c=-4
a-b=10, 3a+b=3
a=10+b, 3(10+b)+b=3
b=-27/4
a=10-27/4
a=13/4
Answer:
Reflection over the X axis.
Answer:
Distance:
units
Step-by-step explanation:
The distance formula is
where:
is the distance between points
and 
are the coordinates of the first point
are the coordinates of the second point
We are given that:
To determine the value of our distance,
, we plug in our given information into the formula and solve for






Therefore, the distance between
and
is
units.
See the attached graph for a visual.