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schepotkina [342]
2 years ago
10

ella purchased a new car in 2000 for $27,600. the value of the car has been depreciating exponentially at a constant rate. if th

e value of the car was $8,300 in the year 2004, then what would be the predicted value of the car in the year 2009, to the nearest dollar?
Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
3 0
Just add and multiply each value of car and chose
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3 years ago
I need help with number five. Thank you much!
s344n2d4d5 [400]
Hey there.

For 5:

We already have been given all the information we need to solve for this- it's just really extensive, so bare with me here.

With our initial deposit of $150 in January, we give 10% of the current value in the following month. This means 10% of 150 will be deposited into the checking account in February, and so on for the rest. I will work this out.

10% of 150 = 15; we deposit $15 into the account in February.
10% of 165 = 16.5; we deposit $16.5 into the account in March.
10% of 181.5 = 18.15; we deposit $18.15 into the account in April.
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10% of 241.57 = 24.157; we deposit $24.15 in July.
10% of 265.72 = 26.572; we deposit $26.57 in August.


Our total value is $292.29, although if we added the thousandths, we'd have $292.31; therefore your answer is going to be D.) $292.31

I hope this helps!
3 0
3 years ago
What is the result when 2x^3-5x^2-x+6 is divided by x+1?
makkiz [27]

(

2

x

−

3

)

(

x

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Factor

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Factor

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using the AC method.

Tap for more steps...

(

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(

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(

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8 0
3 years ago
Simplify: 7·(a+5)–30 =
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7 0
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