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Hoochie [10]
3 years ago
12

Write the equation of a vertical ellipse with a major axis of 20, a minor axis of 12, and a center of (6, 3)

Mathematics
1 answer:
kupik [55]3 years ago
6 0

Answer:

The answer to your question is

Standard form

        \frac{(x - 6)^{2} }{12^{2}} + \frac{(y - 3)^{2} }{20^{2}} = 1

General form

          400x² + 144y² - 4800x - 864y - 41904 = 0

Step-by-step explanation:

Data

Vertical ellipse

Mayor axis = a = 20

Minor axis = b = 12

Center = (6, 3)

Formula

              \frac{(x - h)^{2} }{b^{2}} + \frac{(y - k)^{2} }{a^{2}} = 1

Substitution and standard form

              \frac{(x - 6)^{2} }{12^{2}} + \frac{(y - 3)^{2} }{20^{2}} = 1

General equation

           400(x - 6)² + 144(y - 3)² = 57600

           400(x² - 12x + 36) + 144(y² - 6y + 9)² = 57600

            400x² - 4800x + 14400 + 144y² - 864y + 1296 = 57600

            400x² + 144y² - 4800x - 864y +14400 + 1296 - 57600 = 0

            400x² + 144y² - 4800x - 864y - 41904 = 0

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3 years ago
Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f
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Answer:

\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}

Step-by-step explanation:

The formula of a volume of a square pyramid:

V=\dfrac{1}{3}a^2h

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We have H = 8in.

Substitute and solve for a:

\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}

3 0
3 years ago
A
tamaranim1 [39]

Answer:

3000

Step-by-step explanation:

640x3 = 1920

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7 0
1 year ago
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lyudmila [28]

Answer:

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Step-by-step explanation:

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2 years ago
Read 2 more answers
What is an equation of the line that passes through the points (-2, 1) and (-8, 4)?
Grace [21]

Answer:

<h2>3x + 6y = 0</h2>

Step-by-step explanation:

Equation of a line = y = mx + c

where m = slope

m = (1 - 4) / (-2 - (-8))

<h3>m = -3 / 6</h3>

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2 years ago
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