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Simora [160]
3 years ago
9

( x + y + 2 ) ( y + 1 ) , ILL GIVE BRAINLIST

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0
I think it’s D.y2 +xy+x+3y+2

(Sorry if I’m wrong)
miskamm [114]3 years ago
5 0
The answer is D i’m pretty sure.
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What are the domain and range of the function f(x)= 3^x+5
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Answer:

Step-by-step explanation:

Domain:all real values

Range:[5,∞)

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3 years ago
A television normally sells for $320. This week, it's on sale at 60% of the normal price. What is the sale price?
KIM [24]
60%=60/100=0.60

320*.60=192

Answer=$192
8 0
3 years ago
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Choose the most appropriate translation. The number of cars sold (which depends on the price for the car)
krok68 [10]
. The amount of TIME spent driving (which depends on the SPEED of the car) is 5 hours. means time(speed) = 5. TIME and SPEED are your key words and 5 is the key number.
3 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
I’m need help with the question in general.
navik [9.2K]

Answer:

I Cant  See

Step-by-step explanation:

8 0
3 years ago
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