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Sindrei [870]
3 years ago
13

Pls help if u only know the answer thanks!

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

-6.8

Step-by-step explanation:

Go down by 0.1 each time. Hope I helped.

Rama09 [41]3 years ago
4 0

Answer:

-6.8

Step-by-step explanation:

You might be interested in
Jan 18 Spiral Review<br> Find the surface area of the following complex shapes.
zepelin [54]

Answer:

320 in.²

Step-by-step explanation:

Let's think of the shape as a normal rectangle with a height of 16 inches. Now all we need is the length. If you look at the right corner, it looks like a piece has been cut out. Since that piece has the same length and height of 8 inches, it is a square. This tells us the missing length of the entire length of the rectangle. Now the length of the rectangle is 16 inches + 8 inches, which is 24 inches.

The total area of the rectangle is 16 × 24, which is 384.

Then from the total area, we just need to subtract the area of the cut-out part. The area of the cut-out square is 8 × 8, which is 64.

384 - 64 = 320

The total surface area of the following complex shape is 320 in.²

4 0
2 years ago
Daisy measured the heights of 20 plants.
sergiy2304 [10]

Answer:

  • 30.5 cm

Step-by-step explanation:

<em>Refer to attached</em>

  • Height of plants (h) >> Frequency >> Midpoint >> Frequency x midpoint
  • 0 <h < 10 >>  1  >> 5 >> 5
  • 10 <h < 20 >> 4 >> 15 >>  60
  • 20 <h < 30 >> 7 >> 25 >> 175
  • 30 <h < 40 >> 2 >> 35 >> 70
  • 40 <h < 50 >> 3 >> 45 >> 135
  • 50 <h < 60 >> 3 >> 55 >> 165

Sum of frequencies = 20

Sum of frequency x midpoint product = 610

<u>Mean height </u>

  • 610/20 = 30.5 cm

5 0
4 years ago
How many solutions are there to the equation below?
Art [367]

Answer: B.Infinitely many

3 0
3 years ago
Find the slope plssss
crimeas [40]

Answer:

5/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the
Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy

and I assume <em>C</em> has a positive orientation in both cases

(a) It looks like the region has the curves <em>y</em> = <em>x</em> and <em>y</em> = <em>x</em> ² as its boundary***, so that the interior of <em>C</em> is the set <em>D</em> given by

D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}

• Compute the line integral directly by splitting up <em>C</em> into two component curves,

<em>C₁ </em>: <em>x</em> = <em>t</em> and <em>y</em> = <em>t</em> ² with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}

(b) <em>C</em> is the boundary of the region

D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}

• Compute the line integral directly, splitting up <em>C</em> into 3 components,

<em>C₁</em> : <em>x</em> = <em>t</em> and <em>y</em> = 0 with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = <em>t</em> with 0 ≤ <em>t</em> ≤ 1

<em>C₃</em> : <em>x</em> = 0 and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}

• Using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}

4 0
3 years ago
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