Answer:
e. All of the above are considered species under at least one species concept.
Explanation:
All of the abovementioned conditions satisfy at least one condition of species definition. Further arguments are given below to support each statement,
a. A species is the <u>monophyletic group</u> of individuals who has a <u>common ancestor</u> which could be <u>distinguished from the closest phylogenetic relative</u> based on <u>conserved genes</u> (16S in bacteria and 18S in eukaryotes). In the statement above, beetles satisfy this condition.
b. A species is the group of individuals that are capable of <u>exchanging genes or can interbreed</u>. In the above statement, birds who are interbreeding with each other must be a single species.
c. A metapopulation is generically defined as the group of populations who are <u>separated by space</u> but are the <u>same species according to phylogenetic analysis</u>. Thus, the metapopulation of salamanders who are linked by gene flow (gene migration) should be treated as one species.
d. The word "<u>lineage</u>" already conveys the message that these bacteria belong share <u>sample place in the phylogenetic tree</u> and they are capable to adapt the same environmental niche. Therefore, they should be considered as one species. This can be easily tested via 16S rRNA sequencing.
To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.


0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Answer:
Explanation:
As verbs the difference between mounting and staining is that mounting is while staining is . As an adjective mounting is that continues to mount; steadily accumulating. As a noun mounting is something mounted; an attachment.
<span>Large changes in allele frequencies can occur in a short time - any changes in frequency, occurring as a result of random chance, would have a proportionally larger effect in a small population. </span>
Answer:
The answer is day 14 - / + 3 days
Explanation:
In a 28-day menstrual cycle the most likely days for a woman to become pregnant is from day 14 - / + 3 days, that is, days 11, 12, 13, 14, 15 and 16. She should be educated, If she is in search of pregnancy, take the vaginal temperature and realize how the viscosity of the abundant flow begins to present.