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2 years ago

-3-3x=-4(2x+7) solbe

Mathematics

2 answers:

sveticcg [70]2 years ago

7 0

Answer:

x = -5

Step-by-step explanation:

-3 - 3x = -4( 2x + 7 )

Distributive property

-4 * 2x - 4 * 7

-3 - 3x = -8x - 28

Add 3 on both sides

-3 + 3 - 3x = -8x - 28 + 3

-3x = -8x - 25

Add 8x on both sides

-3x + 8x = -8x + 8x - 25

5x = -25

Divide by 5 on both sides to isolate the variable

5x/5 = -25/5

x = -5

Hope this helped!

have a supercalifragilsticexpialidocious day!

Nostrana [21]2 years ago

5 0

Answer:

x = -5

Step-by-step explanation:

Rearrange terms

-3−3=−4(2+7)

−3−3=−4(2+7)

Distribute

−3−3=−4(2+7)

−3-3=−8−28

Add 3 to both sides of the equation

−3−3=−8−28

−3−3+3=−8−28+3

Simplify

Add the numbers:

−3−3+3=−8−28+3

−3=−8−28+3

Add the numbers:

−3=−8−28+3

−3=−8−25

Add 8 to both sides of the equation

−3=−8−25

−3+8=−8−25+8

Simplify

Combine like terms

−3+8=−8−25+8

5=−8−25+8

Combine like terms

5=−8−25+8

5=−25

Divide both sides of the equation by the same term

5=−25

5x/5 = -25/5

Simplify

Cancel terms that are in both the numerator and denominator

5x/5 = --25/5

x= -25/5

Divide the numbers

x= -25/5

x = -5

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3 years ago

Andrea wanted to calculate 5% of 300, so she multiplied 300 by 0.5 (300 x 0.5).

Mars2501 [29]

This is because Andrea converted the Percentage wrong.
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Andrea should have multiplied 300 by 0.05 instead to get the right answer

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3 years ago

Please help will do anything thank you

kifflom [539]

Answer:

Step-by-step explanation:

a). Stock price arranged as arithmetic sequence will be,

5, 8, 11, 14

b). Since, explicit formula of an arithmetic sequence is given by,

$a_n=a+(n-1)d$

Here, $T_n$ = nth term of the sequence

a = first term

n = number of term

d = common difference

From the table attached,

First term of the sequence 'a' = 5

Common difference 'd' = 8 - 5 = 3

Therefore, explicit formula for the given sequence will be,

$a_n=5+3(n-1)$

$a_n=2+3n$

c). Slope intercept form of the equation will be,

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3 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

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Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

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3 years ago