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3 years ago

6 divide by 1/3???????

Mathematics

2 answers:

yarga [219]3 years ago

8 0

Answer:

Step-by-step explanation:

1/3 = .3

6/.3 = 20

Lyrx [107]3 years ago

8 0

Answer:

Step-by-step explanation:

6 ÷ 1/3

changing the ÷ sign into × sign and taking reciprocal of the second term

6 × 3/1

putting 1 as the denominator of 6

6/1 × 3/1

now multiplying both terms

18/1

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PLEASE HELP WITH THISS.......

Mashcka [7]

GF = ½ RT

Step-by-step explanation:

SG=GR (given)

SF=FT (given)

line GF is a midpoint in triangle RST, so it is therefore ½ the angle parallel to it(viz. RT)

5 0

3 years ago

Math how to learn more abt it

alukav5142 [94]

Answer:

To learn more about math, you need to practice it, and when you have mistakes, understand it better then you'll get it. And ask a teacher or adult for help when needed.

Step-by-step explanation:

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2 years ago

Simplify (7-8i)+(-12-4i)

Nutka1998 [239]

(7-8i)+(-12-4i)

=7-8i-12-4i

=-5-12i

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3 years ago

Read 2 more answers

Kiran and Mai are trying to figure out if this equation is an identity, what do you think

ValentinkaMS [17]

Expanding the left side of the equation, it is found that since both sides are equal, yes, it is an identity.

An equality represents an identity if both sides are equal.

In this problem:

$(a - b)^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Expanding the left side:

$(a - b)^2(a - b)^2 = a^4 - 4a^3b + 6a^2b^2 + 4ab^3 + b^4$

$(a^2 - 2ab + b^2)(a^2 - 2ab + b^2) = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

$a^4 - 4a^3b + + 6a^2b^2 - 4ab^3 + b^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Since both sides are equal, yes, it is an identity.

A similar problem is given at brainly.com/question/24866308

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2 years ago

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Gekata [30.6K]

7.)9.68
8.)600
9.)7
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16.) 36
17.) -34, -27, -13, 12, 36, 63

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3 years ago