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lana [24]
2 years ago
14

7+x=32 solve the equation

Mathematics
2 answers:
svlad2 [7]2 years ago
5 0

Answer: x=25

Step-by-step explanation:

7+x=32 (subtract 7)

x=25

Evgesh-ka [11]2 years ago
3 0
X=25 so that you let answer
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Does the image reflect over the x or y axis ?
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x- axis, I'm pretty sure

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Which is the simplified form of the expression (co?x237) : (604x2")​
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3 years ago
Whilst shopping, the probability that Caroline buys fruit is 0.7.
Lilit [14]

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Probability that Caroline buys fruit, a CD or both is 0.76.

Step-by-step explanation:

Let event A = Caroline buys fruit, event B = Caroline buys CD, Ac and Bc are complementary events.

Events AB, ABc, AcB and AcBc are jointly exhaustive and disjoint, hence P(AB) + P(ABc) + P(AcB) +P(AcBc) =1.

Events A and B independent, hence Ac and Bc independent too and probability P(AcBc) = P(Ac)*P(Bc) = (1 - P(A))(1-P(B)) = 0.6*0.4 = 0.24.

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3 0
2 years ago
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Randy spins the arrow on a spinner with 5 equal sections labeled A,B,C,D, and EVEN. Then ,he rolls a 6-sided number cube with si
aivan3 [116]
You have 1 out of 5 chances to get a A in the spinner 
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8 0
3 years ago
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1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr
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Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

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P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

7 0
3 years ago
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