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olchik [2.2K]
3 years ago
9

Help on math question

Mathematics
2 answers:
docker41 [41]3 years ago
6 0

Answer:

A

Step-by-step explanation:

f(x) = 3 is a horizontal line. Since the boundary is x<1 then it points left with an open circle. This means only A and D are options.

f(x) = x is a diagonal line. Since D does not have a diagonal line, A is the solution.

yulyashka [42]3 years ago
6 0

Answer:

The answer is A.

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What’s the answer to this?
sattari [20]

Answer:

14.42

Step-by-step explanation:

6 0
3 years ago
Write the equation of a line, in SLOPE INTERCEPT FORM, that is perpendicular to the given equation and passes through the given
adoni [48]

Step-by-step explanation:

slope interception formula is

y-y1=m(x-x1)

where m is m=y-y1/x-x1 in this case m=-2 because the line we are trying to find is parallel to the given one y=-2x-6 where slope k=-2

so the final equation would be

y-1=-2(x-(-4))

y-1=-2x-2*4

y=-2x-8+1=-2x-7

4 0
3 years ago
What is the relationship between the graphs of f(x) = x^2 and g(x) = x^2 + 6?
Tamiku [17]
They have the same slope, but g(x) intercepts the y axis higher.
6 0
1 year ago
Leila, Charlie, and Joe have a total of $144 in their wallets. Joe has 4 times what Leila has. Charlie has $6 more than Leila. H
ollegr [7]

Answer:

The amounts of money each has are:

Joe = $92

Charlie = $29

Leila = $23

Step-by-step explanation:

To solve this, we will convert the statements into an equation, and use that to solve for the unknowns, as follows:

total amount = $144

Let Leila's share be S

Joe's share = 4 times Leila's = 4S

Charlie's share = $6 + Leila's share = 6 + S

Joe's share + Charlie's Share + Leila's Share = $144

4S + (6 + S) + S = 144

4S + 6 + S + S = 144

4S + 2S + 6 = 144

6S + 6 = 144

6S = 144 - 6 = 138

S = 138 ÷ 6 = $23

Therefore Leila's share 'S' = $23

Joe share= 4S = 4 × 23 = $92

Charlie's share = 6 + 23 = $29

8 0
3 years ago
Is 81 a multiple of 3? Explain, Is 46 a multiple of 4, Explain, Is 55 a multiple of 7? Explain Is 72 a multiple of 9 explain, Is
ra1l [238]
3x27=81 so 81 is a multiple of 3

there is no integer x for which 4x=46 so 46 is not a multiple of 4

there is no integer x for which 7x=55 so 55 is not a multiple of 7

72 = 8*9 so 72 is a multiple of 9

there is no integer x for which 6x=45 hence 45 is not a multiple of 6
6 0
3 years ago
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