3 years ago

Please help, I will give brainliest to whoever helps!

Mathematics

1 answer:

Olin [163]3 years ago

4 0

Answer: 0 solutions, II only, 1 solution

Step-by-step explanation:

When the first equation is factored, there are no real solutions that can be found. b^2 - 4ac has to be greater than 0 to have two solutions. x^2 + 2x + 1 is (x + 1) ^ 2, so there is one solution.

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