<img src="https://tex.z-dn.net/?f=%20%7B%28%20%5Cfrac%7B5%7D%7B3%7D%20%29%7D%5E%7B2n%20%2B%201%7D%20%20%7B%28%20%5Cfrac%7B5%7D%7

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2 years ago

B3%7D%20%29%7D%5E%7B5%7D%20%20%3D%20%20%28%7B%20%5Cfrac%7B5%7D%7B3%7D%20%29%7D%5E%7Bn%20%2B%202%7D%20" id="TexFormula1" title=" {( \frac{5}{3} )}^{2n + 1} {( \frac{5}{3} )}^{5} = ({ \frac{5}{3} )}^{n + 2} " alt=" {( \frac{5}{3} )}^{2n + 1} {( \frac{5}{3} )}^{5} = ({ \frac{5}{3} )}^{n + 2} " align="absmiddle" class="latex-formula">
Pls include steps...

Mathematics

1 answer:

Alisiya [41]2 years ago

5 0

Answer:

n = -4

Step-by-step explanation:

$(\frac{5}{3} )^2^n^+^1 * (\frac{5}{3} )^5 = (\frac{5}{3})^n^+^2$

in multiplication if the base are same u can add there exponent.

$(\frac{5}{3})^2^n^+^1^+^5 = (\frac{5}{3})^n^+^2$

base of both sides are equal so their exponent will be equal

2n + 1 + 5 = n + 2

2n + 6 = n + 2

2n - n = 2 - 6

n = -4

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