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lana66690 [7]
4 years ago
15

According toThe Humane Society in 2009 33% of US households owned at least one cat and 56% of households who did own cats owned

at least 2. the US Census Bureau tells us that there were 116 million households in 2009 how many households owned at least two cats report your answer in millions around the two places
Mathematics
1 answer:
taurus [48]4 years ago
7 0

Answer:

<h2>21.4368 ≅ 21.44 million households owned at least two cats.</h2>

Step-by-step explanation:

Total number of households were 116 million.

Hence, 100% = 116 million.

33% of the total US households owned at least one cat.

Hence, the number of household having at least one cat is \frac{33\times116}{100} = \frac{3828}{100} = 38.28 million.

It is also given that 56% of that 38.28 million households owned at least 2 cats.

Hence, the number of households having 2 cats is \frac{56\times38.28}{100} = \frac{2143.68}{100} = 21.4368 million.

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An ordinary fair die is a cube with the numbers one through six on the sides represented by painted that. Imagine that such a di
Solnce55 [7]

Answer:

ok so what i think your trying to ask is if we roll two dice that the sum will be more then 6

Two dice

Assuming that the dice are unbiased or not " loaded".

Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.

How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?

These are the possibilities

Case 1.

D1 =1 & D2=5

Or

D1= 5 & D2=1

Case 2.

D1 =2 & D2=4

Or

D1= 4 & D2= 2

Case 3. D1=3, D2=3

P3 =0.027778

Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.

The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.

P1= 0.02778+ 0.02778 =0.055558

P2= 0.02778+0.02778 =0.055558

Same way,

P3=0.027778, when there is only one way to get the sum 6.

So, P = 0.138894

Based on truncating at the sixth decimal place.

A visual representation with two unbiased dice and the possible cases would also give the same result and is a short cut method. I like to derive from the basics.

Hope This Helps!!!

6 0
3 years ago
Which of the following statements is true?
Murrr4er [49]

Option A - (0,0) is a solution to both the equations. is the only true statement.

Step-by-step explanation:

Step 1 :    

Given  2 equations are

n = m

n = 4m

Step 2:

(0,0) is a solution to both the equations.

This statement is true as substituting the point , the equations are true.

Step 3 :

Every solution to n=m is also a solution to n=4 m

Take the point (5,5)

This point lies on the equation n = m, as both the x and y co ordinates are same

n = 4 m = 4 × 5 = 20

So here for n = 5, n = 4 m is not true and hence this point is not a solution for the second equation thought it is a solution for the first equation

Hence this statement is not true

Step 4:

The graph of the solutions is  parallel lines

this statement is not true because the 2 lines intersect at (0,0) as observed from step 2.

Step 5 :

No point on the line n=m is also a point on n=4 m

This statement is not true because (0,0) is a point on both the lines.

Step 6 :

Answer :

Option A - (0,0) is a solution to both the equations. is the only true statement.

6 0
3 years ago
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